Question

我无法使用“doLogicForColumn5”功能来影响我的程序。 CSV输出的第5列应填充各种值，但它们都是相同的数字（12.12）。

第14-27行具体 - 他们根本不工作！

任何帮助都非常感谢！

     # -*- coding: utf-8 -*-
import csv
import string # for capwords
date = "7/5/2015"
monthlybudget = 100000
dailybudget = monthlybudget/30
#campaign variables
levels = [["1"], ["2"], ["3"], ["4"], ["5"], ["6"]]
language = [["english"], ["spanish"]]
variables = [["1"], ["2"]]
nouns = [["wordA1"], ["+wordA2"]]
adjectives1 = [["wordB1"], ["wordB2"]]
adjectives2 = [["wordC1"], ["wordC2"]]
def doLogicForColumn5(self): # budget
    self.column5 = dailybudget/36 
    if self.language == ["spanish"]: 
        self.column5 = self.column5 * .6
        if self.level == ["1"]:
            self.column5 = self.column5*.8
        else:
            self.column5 = self.column5*.1
    else: #if spanish
        self.column5 = self.column5*.4
        if self.level == ["1"]:
            self.column5 = self.column5*.2
        else:
            self.column5 = self.column5*.3
class Row(object):
    column1 = "column1"
    column2 = "column2"
    column3 = "column3"
    column4 = "column4"
    column5 = "budget"
    def __init__(self, level, language, noun, adjective1, adjective2, variable):
        self.level = level
        self.level = str(self.level)
        self.language = language
        self.language = str(self.language)
        self.noun = noun
        self.noun = str(self.noun)
        self.adjective1 = adjective1
        self.adjective1 = str(self.adjective1)
        self.adjective2 = adjective2
        self.adjective2 = str(self.adjective2)
        self.variable = variable
        self.variable = str(self.variable)
    def rowEntry(self, level, language, noun, adjective1, adjective2, variable):
        doLogicForColumn5(self)
        lol = [[self.column1], [self.column2], [self.column3], [self.column4], [self.column5]]
        lol[0] = self.column1
        lol[1] = self.column2
        lol[2] = self.column3
        lol[3] = self.column4
        lol[4] = self.column5
        file_writer.writerow([o for o in lol])
with open("test.csv", "wb") as test_file:
    file_writer = csv.writer(test_file)
    for a in range(0, len(levels)):
        for e in range(0, len(language)):    
            for y in range (0, len(nouns)):
                for x in range (0, len(adjectives1)):
                    for w in range (0, len(adjectives2)):
                        for n in range(0, len(variables)):
                            city = "n/a"
                            stateVersion = "n/a"
                            food = Row(levels[a], language[e], nouns[y], adjectives1[x], adjectives2[w], variables[n])                    
                            food.rowEntry(levels[a], language[e], nouns[y], adjectives1[x], adjectives2[w], variables[n])

Answer 1

首先：

for a in range(0, len(levels)):

所以a是一个数字。然后：

food = Row(levels[a],

所以levels[a]是list，例如["1"]。然后，当您__init__() Row：

时

self.level = level
self.level = str(self.level)

所以现在self.level是一个字符串。然后，在doLogicForColumn5()：

if self.level == ["1"]

回想一下，self.level之前被转换为字符串。因此self.level永远不会等于list ["1"]。但是，它可能等于"['1']"的字符串，因此与它进行比较会更有意义。更好的是，将全局levels变为像list这样的单["1", "2", "3", "4", "5", "6"]。最好的选择是levels简单地'123456'并重构您的程序以使用更简单的结构。

同样适用于self.language以及在较大list内已设置为单个元素list的任何其他变量。

检查代码中是否有其他不必要复杂的实例，因为这种事情最终会让你感到困惑（另一个例子，doLogicForColumn5()函数应该只是Row中的一个方法，因为评论者是提示）。

Python中的简单逻辑错误 - 我的函数调用无法正常工作

1 个答案: