Question

我试图在C＃中编写Heap算法的实现，但这种实现无法正常工作。我正在尝试创建一个通用实现，它将查找字符串的所有排列，并将它们添加到列表中。

我是这样开始的：

List<string> permutations = new List<string>();
GenerateHeapPermutations(3, "ABC", permutations);

foreach (var p in permutations)
{
    Console.WriteLine(p);
}

Console.ReadKey();

这是我的实施：

public static void GenerateHeapPermutations(int n, string s, List<string> sList)
{
    if (n == 1)
    {
        sList.Add(s);
    }
    else
    {
        for (int i = 0; i < n - 1; i++)
        {
            GenerateHeapPermutations(n - 1, s, sList);

            if (n % 2 == 0)
            {
                // swap the positions of two characters
                var charArray = s.ToCharArray();
                var temp = charArray[i];
                charArray[i] = charArray[n - 1];
                charArray[n - 1] = temp;
                s = new String(charArray);
            }
            else
            {
                var charArray = s.ToCharArray();
                var temp = charArray[0];
                charArray[0] = charArray[n - 1];
                charArray[n - 1] = temp;
                s = new String(charArray);
            }
        }

        GenerateHeapPermutations(n - 1, s, sList);
    }
}

该算法确实产生了正确的排列数（在本例中为6），但排列本身是不正确的：

ABC       BAC       CBA               
BCA       ABC       BAC

我不认为我偏离了pseudocode example of Heap's algorithm on Wikipedia，而且我很难调试这个因为这个算法的递归性质（概念化非常棘手）。

任何人都可以提供任何有关问题的见解吗？

^{P.S。不是作业，只是为了好玩。}

Answer 1

您的算法基于传递string而不是实际数组。传递string时会获取字符串的副本，因此更改复制的字符串不会更改传递的实际字符串。

将string更改为char array时，问题就解决了。

public static void Main()
{
    List<string> permutations = new List<string>();
    GenerateHeapPermutations(3, new [] { 'A', 'B', 'C' }, permutations);

    foreach (var p in permutations)
    {
        Console.WriteLine(p);
    }

    Console.ReadKey();
}

public static void GenerateHeapPermutations(int n, char[] charArray, List<string> sList)
{
    if (n == 1)
    {
        sList.Add(new string(charArray));
    }
    else
    {
        for (int i = 0; i < n - 1; i++)
        {
            GenerateHeapPermutations(n - 1, charArray, sList);

            int indexToSwapWithLast = (n%2 == 0 ? i : 0);
            // swap the positions of two characters
            var temp = charArray[indexToSwapWithLast];
            charArray[indexToSwapWithLast] = charArray[n - 1];
            charArray[n - 1] = temp;
        }

        GenerateHeapPermutations(n - 1, charArray, sList);
    }
}

注意：您可以使用n删除冗余数字charArray.Length输入，并从数组长度派生，但我不想不必要地更改你的代码。

Answer 2

首先要做的事：调试。在处理递归时，调试代码的最简单方法是在IDE中设置断点并逐步逐步执行，记下代码的行为方式。这允许您在每一步查看变量的值。

你会发现在任何地方传递你的字符串并没有产生你所期望的，因为你传递的是它的副本而不是实际值。如果你通过引用传递（不确定C＃是否允许），你就会做你期望的事。

Answer 3

我会通过引用传递参数;这产生了预期的输出。

 string sample = "ABC";
            List<string> permutations = new List<string>();
            GenerateHeapPermutations(3, ref sample, permutations);

            foreach (var p in permutations)
            {
                System.Console.WriteLine(p);
            }

            System.Console.ReadKey();




public static void GenerateHeapPermutations(int n, ref string s, List<string> sList)
        {
            if (n == 1)
            {
                sList.Add(s);
            }
            else
            {
                for (int i = 0; i < n - 1; i++)
                {
                    GenerateHeapPermutations(n - 1, ref s, sList);

                    if (n % 2 == 0)
                    {
                        // swap the positions of two characters
                        var charArray = s.ToCharArray();
                        var temp = charArray[i];
                        charArray[i] = charArray[n - 1];
                        charArray[n - 1] = temp;
                        s = new String(charArray);
                    }
                    else
                    {
                        var charArray = s.ToCharArray();
                        var temp = charArray[0];
                        charArray[0] = charArray[n - 1];
                        charArray[n - 1] = temp;
                        s = new String(charArray);
                    }
                }

                GenerateHeapPermutations(n - 1, ref s, sList);
            }
        }

Answer 4

也许我的实施可以帮助你...

我认为这是最快的......

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Runtime.CompilerServices;

namespace WpfPermutations
{
    /// <summary>
    /// EO: 2016-04-14
    /// Generator of all permutations of an array of anything.
    /// Base on Heap's Algorithm. See: https://en.wikipedia.org/wiki/Heap%27s_algorithm#cite_note-3
    /// </summary>
    public static class Permutations
    {
        /// <summary>
        /// Heap's algorithm to find all pmermutations. Non recursive, more efficient.
        /// </summary>
        /// <param name="items">Items to permute in each possible ways</param>
        /// <param name="funcExecuteAndTellIfShouldStop"></param>
        /// <returns>Return true if cancelled</returns> 
        public static bool ForAllPermutation<T>(T[] items, Func<T[], bool> funcExecuteAndTellIfShouldStop)
        {
            int countOfItem = items.Length;

            if (countOfItem <= 1)
            {
                return funcExecuteAndTellIfShouldStop(items);
            }

            var indexes = new int[countOfItem];
            for (int i = 0; i < countOfItem; i++)
            {
                indexes[i] = 0;
            }

            if (funcExecuteAndTellIfShouldStop(items))
            {
                return true;
            }

            for (int i = 1; i < countOfItem;)
            {
                if (indexes[i] < i)
                { // On the web there is an implementation with a multiplication which should be less efficient.
                    if ((i & 1) == 1) // if (i % 2 == 1)  ... more efficient ??? At least the same.
                    {
                        Swap(ref items[i], ref items[indexes[i]]);
                    }
                    else
                    {
                        Swap(ref items[i], ref items[0]);
                    }

                    if (funcExecuteAndTellIfShouldStop(items))
                    {
                        return true;
                    }

                    indexes[i]++;
                    i = 1;
                }
                else
                {
                    indexes[i++] = 0;
                }
            }

            return false;
        }

        /// <summary>
        /// This function is to show a linq way but is far less efficient
        /// From: StackOverflow user: Pengyang : http://stackoverflow.com/questions/756055/listing-all-permutations-of-a-string-integer
        /// </summary>
        /// <typeparam name="T"></typeparam>
        /// <param name="list"></param>
        /// <param name="length"></param>
        /// <returns></returns>
        static IEnumerable<IEnumerable<T>> GetPermutations<T>(IEnumerable<T> list, int length)
        {
            if (length == 1) return list.Select(t => new T[] { t });

            return GetPermutations(list, length - 1)
                .SelectMany(t => list.Where(e => !t.Contains(e)),
                    (t1, t2) => t1.Concat(new T[] { t2 }));
        }

        /// <summary>
        /// Swap 2 elements of same type
        /// </summary>
        /// <typeparam name="T"></typeparam>
        /// <param name="a"></param>
        /// <param name="b"></param>
        [MethodImpl(MethodImplOptions.AggressiveInlining)]
        static void Swap<T>(ref T a, ref T b)
        {
            T temp = a;
            a = b;
            b = temp;
        }

        /// <summary>
        /// Func to show how to call. It does a little test for an array of 4 items.
        /// </summary>
        public static void Test()
        {
            ForAllPermutation("123".ToCharArray(), (vals) =>
            {
                Console.WriteLine(String.Join("", vals));
                return false;
            });

            int[] values = new int[] { 0, 1, 2, 4 };

            Console.WriteLine("Ouellet heap's algorithm implementation");
            ForAllPermutation(values, (vals) =>
            {
                Console.WriteLine(String.Join("", vals));
                return false;
            });

            Console.WriteLine("Linq algorithm");
            foreach (var v in GetPermutations(values, values.Length))
            {
                Console.WriteLine(String.Join("", v));
            }

            // Performance Heap's against Linq version : huge differences
            int count = 0;

            values = new int[10];
            for (int n = 0; n < values.Length; n++)
            {
                values[n] = n;
            }

            Stopwatch stopWatch = new Stopwatch();

            ForAllPermutation(values, (vals) =>
            {
                foreach (var v in vals)
                {
                    count++;
                }
                return false;
            });

            stopWatch.Stop();
            Console.WriteLine($"Ouellet heap's algorithm implementation {count} items in {stopWatch.ElapsedMilliseconds} millisecs");

            count = 0;
            stopWatch.Reset();
            stopWatch.Start();

            foreach (var vals in GetPermutations(values, values.Length))
            {
                foreach (var v in vals)
                {
                    count++;
                }
            }

            stopWatch.Stop();
            Console.WriteLine($"Linq {count} items in {stopWatch.ElapsedMilliseconds} millisecs");
        }
    }
}

Heap算法的C＃实现不起作用

4 个答案: