Question

我遇到python有关计算到下一个生日的时间长短的问题。这是我的代码：

import datetime
currentDate=datetime.date.today()
userInput=raw_input('please enter your birthday(dd/mm/yyyy)')
birthday = datetime.datetime.strptime(userInput,'%d/%m/%Y').date()
days=birthday-currentDate
print(days)

它给我回答的答案是-6930。

当它给我答案的时候，我试图把它分解成这样的部分：

import datetime
currentDate=datetime.date.today()
userInput=raw_input('please enter your birthday(dd/mm/yyyy)')
birthday = datetime.datetime.strptime(userInput,'%d/%m/%Y').date()
months =birthday.month-currentDate.month 
days = birthday.day-currentDate.day
print('your next birthday is in ' +str(months) +' months and '+ str(days) + 'days' )

然后可以输入月份等于或大于当月，所以当我输入时输入：18/09/1996它给出了答案“你的下一个生日是2个月和9天“但是如果输入的月份小于当前月份：18/05/1996它给我回答的答案是”旅游生日是-2个月和9天“

希望你能帮助我:)。

Answer 1

要获取下一个生日的日期，获取月份和月份之间的差异是不够的。

首先，将生日转移到今年;你可能想要处理闰年：

birthday = datetime.datetime.strptime(userInput, '%d/%m/%Y').date()
today = datetime.date.today()
try:
    next_birthday = birthday.replace(year=today.year)
except ValueError:
    # oops, not a leapyear this year, no february 29th; use the day before
    next_birthday = birthday.replace(day=28, year=today.year)

if next_birthday < today:  # already passed this year, pick next year
    try:
        next_birthday = birthday.replace(year=today.year + 1)
    except ValueError:
        # oops, not a leapyear next year, no february 29th, use the day before
        next_birthday = birthday.replace(day=28, year=today.year + 1)

difference = next_birthday - today
months, days = divmod(difference.days, 30)  # assume 30 days per month
print 'Your birthday is in about {} months and {} days'.format(months, days)

Answer 2

您是否可以执行以下操作？：

如果它大于当年的生日月/日，则从你的生日NEXT年中减去当前日期。

否则，您今年的生日没有到来，所以从今年的生日中减去当前日期。

python给了我错误的答案，直到我的下一个生日

2 个答案: