Question

假设is.character(MyColours) = TRUE其中MyColours包含许多十六进制颜色值。

我如何确保当我想使用ggplot绘图时，我可以确保MyColours [1]将始终用于表示“Ford”，MyColour [3]将代表“Toyota”，当我无法保证订单时“福特”或“丰田”将出现在我用来绘制的观察中。

虽然下面的geo_bar示例很有用，但确实提醒我将列名称添加到MyColours我希望绘制的行不是条形

    ggplot(MyData, aes(x = TimePeriod, y = CountOfItems, 
group = Account, color = scale_fill_manual(values = MyColours))) 
    + geom_line(size = 1) 
    + theme(axis.text.x = element_text(angle = 90, vjust = 0.5, hjust=1))

即使Aesthetics must either be length one, or the same length as the dataProblems:scale_fill_manual(values = MyColours)等于length(MyColours)

，我也会收到错误length(unique(MyData$Account))

示例数据

dput(MyData)
structure(list(Account = structure(c(1L, 2L, 1L, 2L), .Label = c("Mazda RX4", 
"Toyota Corolla"), class = "factor"), CountOfItems = c(14, 120, 
23, 345), TimePeriod = structure(c(1L, 2L, 2L, 3L), .Label = c("2010-12", 
"2011-01", "2011-02"), class = "factor")), .Names = c("Account", 
"CountOfItems", "TimePeriod"), row.names = c(NA, -4L), class = "data.frame")

是否可以将scale_fill_manual与线图一起使用？

Answer 1

您可以命名MyColours，例如像这样：

MyColour <- c("#FF0000", "#00FF00", "#0000FF") 
names(MyColour) <- c("Mazda RX4", "Toyota Corolla", "Fiat 128")

df <- mtcars[c("Mazda RX4", "Toyota Corolla", "Fiat 128"), ]
df$car <- rownames(df)
library(ggplot2)
ggplot(df, aes(x = car, y = mpg, fill = car)) +
  geom_bar(stat = "identity") + 
  scale_fill_manual(values = MyColour)

使用r和ggplot如何指定用于表示不同字符值的特定十六进制颜色/颜色值

1 个答案: