我正在实施待办事项列表。用户可以有多个列表,列表可以有多个用户。我希望能够检索用户的所有列表,其中每个列表都包含它共享的用户列表(包括所有者)。没有成功实现此查询。
表格定义:
case class DBList(id: Int, uuid: String, name: String)
class Lists(tag: Tag) extends Table[DBList](tag, "list") {
def id = column[Int]("id", O.PrimaryKey, O.AutoInc) // This is the primary key column
def uuid = column[String]("uuid")
def name = column[String]("name")
// Every table needs a * projection with the same type as the table's type parameter
def * = (id, uuid, name) <> (DBList.tupled, DBList.unapply)
}
val lists = TableQuery[Lists]
case class DBUser(id: Int, uuid: String, email: String, password: String, firstName: String, lastName: String)
// Shared user projection, this is the data of other users which a user who shared an item can see
case class DBSharedUser(id: Int, uuid: String, email: String, firstName: String, lastName: String, provider: String)
class Users(tag: Tag) extends Table[DBUser](tag, "user") {
def id = column[Int]("id", O.PrimaryKey, O.AutoInc) // This is the primary key column
def uuid = column[String]("uuid")
def email = column[String]("email")
def password = column[String]("password")
def firstName = column[String]("first_name")
def lastName = column[String]("last_name")
def * = (id, uuid, email, password, firstName, lastName) <> (DBUser.tupled, DBUser.unapply)
def sharedUser = (id, uuid, email, firstName, lastName) <> (DBSharedUser.tupled, DBSharedUser.unapply)
}
val users = TableQuery[Users]
// relation n:n user-list
case class DBListToUser(listUuid: String, userUuid: String)
class ListToUsers(tag: Tag) extends Table[DBListToUser](tag, "list_user") {
def listUuid = column[String]("list_uuid")
def userUuid = column[String]("user_uuid")
def * = (listUuid, userUuid) <> (DBListToUser.tupled, DBListToUser.unapply)
def pk = primaryKey("list_user_unique", (listUuid, userUuid))
}
val listToUsers = TableQuery[ListToUsers]
我创建了一个额外的类来保存数据库列表对象+用户,我的目标是将查询结果以某种方式映射到此类的实例。
case class DBListWithSharedUsers(list: DBList, sharedUsers: Seq[DBSharedUser])
这是大多数的SQL查询,它首先得到用户的所有列表(内部查询)然后它与list_user和用户进行列表连接,以便获取其余数据和用户每个列表,然后它使用内部查询进行过滤。它没有按部分包含该组
select * from list inner join list_user on list.uuid=list_user.list_uuid inner join user on user.uuid=list_user.user_uuid where list.uuid in (
select (list_uuid) from list_user where user_uuid=<myUserUuuid>
);
我测试了它并且它有效。我试图在Slick中实现它,但我收到编译器错误。我也不知道那部分的结构是否正确,但是还没有能够找到更好的结构。
def findLists(user: User) = {
val listsUsersJoin = listToUsers join lists join users on {
case ((listToUser, list), user) =>
listToUser.listUuid === list.uuid &&
listToUser.userUuid === user.uuid
}
// get all the lists for the user (corresponds to inner query in above SQL)
val queryToGetListsForUser = listToUsers.filter(_.userUuid===user.uuid)
// map to uuids
val queryToGetListsUuidsForUser: Query[Rep[String], String, Seq] = queryToGetListsForUser.map { ltu => ltu.listUuid }
// create query that mirrors SQL above (problems):
val queryToGetListsWithSharedUsers = (for {
listsUuids <- queryToGetListsUuidsForUser
((listToUsers, lists), users) <- listsUsersJoin
if lists.uuid.inSet(listsUuids) // error because inSet requires a traversable and passing a ListToUsers
} yield (lists))
// group - doesn't compile because above doesn't compile:
queryToGetListsWithSharedUsers.groupBy {case (list, user) =>
list.uuid
}
...
}
我该如何解决这个问题?
提前致谢
修改:
我把这个紧急解决方案(至少它编译)放在一起,我使用原始SQL执行查询,然后以编程方式进行分组,它看起来像这样:
case class ResultTmp(listId: Int, listUuid: String, listName: String, userId:Int, userUuid: String, userEmail: String, userFirstName: String, userLastName: String, provider: String)
implicit val getListResult = GetResult(r => ResultTmp(r.nextInt, r.nextString, r.nextString, r.nextInt, r.nextString, r.nextString, r.nextString, r.nextString, r.nextString))
val a = sql"""select (list.id, list.uuid, list.name, user.id, user.uuid, user.email, user.first_name, user.last_name, user.provider) from list inner join list_user on list.uuid=list_user.list_uuid inner join user on user.uuid=list_user.user_uuid where list.uuid in (
select (list_uuid) from list_user where user_uuid=${user.uuid}
);""".as[ResultTmp]
val result: Future[Vector[ResultTmp]] = db.run(a)
val res: Future[Seq[DBListWithSharedUsers]] = result.map {resultsTmp =>
val myMap: Map[String, Vector[ResultTmp]] = resultsTmp.groupBy { resultTmp => resultTmp.listUuid }
val r: Iterable[DBListWithSharedUsers] = myMap.map {case (listUuid, resultsTmp) =>
val first = resultsTmp(0)
val list = DBList(first.listId, listUuid, first.listName)
val users: Seq[DBSharedUser] = resultsTmp.map { resultTmp =>
DBSharedUser(resultTmp.userId, resultTmp.userUuid, resultTmp.userEmail, resultTmp.userFirstName, resultTmp.userLastName, resultTmp.provider)
}
DBListWithSharedUsers(list, users)
}
r.toSeq
}
但这太可怕了,我如何让它以正常的方式运作?
编辑2:
我正在尝试使用monadic连接,但也被困在这里。例如,像这样的东西将获得给定用户的所有列表:
val listsUsersJoin = for {
list <- lists
listToUser <- listToUsers
user_ <- users if user_.uuid === user.uuid
} yield (list.uuid, list.name, user.uuid, user.firstName ...)
但这还不够,因为我还需要得到这些列表的所有用户,所以我需要2个查询。因此,我需要首先获得用户的列表,然后找到这些列表的所有用户,例如:
val queryToGetListsForUser = listToUsers.filter(_.userUuid===user.uuid)
val listsUsersJoin = for {
list <- lists
listToUser <- listToUsers
user_ <- users /* if list.uuid is in queryToGetListsForUser result */
} yield (list.uuid, list.name, user.uuid, user.firstName ... )
但我不知道如何将其传递给联盟。我甚至不确定groupBy,至少在数据库级别是否正确,到目前为止我看到这只用于将结果聚合为单个值,如count或avg。我需要他们收藏。
编辑3:
我还不知道这是否正确但是monadic join可能是解决方案的途径。这编译:
val listsUsersJoin = for {
listToUser <- listToUsers if listToUser.userUuid === user.uuid // get the lists for the user
list <- lists if list.uuid === listToUser.listUuid // join with list
listToUser2 <- listToUsers if list.uuid === listToUser.listUuid // get all the users for the lists
user_ <- users if user_.uuid === listToUser2.userUuid // join with user
} yield (list.uuid, list.name, user.uuid, user.email, user.firstName, user.lastName)
答案 0 :(得分:1)
val listsUsersJoin = for {
listToUser <- listToUsers if listToUser.userUuid === user.uuid
list <- lists if list.uuid === listToUser.listUuid
listToUser2 <- listToUsers if list.uuid === listToUser.listUuid
user_ <- users if user_.uuid === listToUser2.userUuid
} yield (list.id, list.uuid, list.name, user_.id, user_.uuid, user_.email, user_.firstName, user_.lastName, user_.provider)
val grouped = listsUsersJoin.groupBy(_._2)
val resultFuture = db.run(grouped.result).flatMap {groupedResults =>
val futures: Seq[Future[DBListWithSharedUsers]] = groupedResults.map {groupedResult =>
val listUuid = groupedResult._1
val valueQuery = groupedResult._2
db.run(valueQuery.result).map {valueResult =>
val first = valueResult(0) // if there's a grouped result this should never be empty
val list = DBList(first._1, listUuid, first._3)
val users = valueResult.map {value =>
DBSharedUser(value._4, value._5, value._6, value._7, value._8, value._9)
}
DBListWithSharedUsers(list, users)
}
}
Future.sequence(futures)
}