Question

我有一张表，列出了工作和工单信息。每个工作至少有一个工单，大多数工作都有很多工单。一些工单可以有子工单，也可以有子工。这为我们提供了多层次的层次结构。

对于我正在构建的报告，我想按照它们所属的二级工作订单对所有工单进行分组。我称之为SectorWO。

我编写了以下查询，几乎达到了我正在寻找的目标，但它不包括二级工作单本身。我试图在SQL Fiddle上构建示例数据，但我的查询不会在那里运行（但它确实在生产SQL Server 2012上运行）。在填充所述表的语句被终止后查询临时表似乎是个问题？

无论如何，这是我在SQL Fiddle上构建的，希望它足以证明......

架构：

CREATE TABLE WOMaster (WorkOrder VARCHAR(12), ParentWorkOrder VARCHAR(12), Job VARCHAR(12))
INSERT INTO WOMaster (WorkOrder, ParentWorkOrder, Job)
VALUES (1,NULL,101),(2,1,101),(3,2,101),(4,3,101),(5,4,101),(6,4,101),(7,4,101),(8,4,101),(9,2,101),(10,2,101),
    (11,2,101),(12,1,101),(13,12,101),(14,12,101),(15,12,101),(16,2,101),(17,1,101),(18,17,101),(19,17,101),(20,1,101),
    (21,1,101),(22,21,101),(23,22,101),(24,22,101),(25,24,101),(26,24,101),(27,1,101),(28,27,101),(29,28,101),
    (30,1,101),(31,30,101),(32,31,101),(33,32,101),(34,1,101),(35,34,101),(36,35,101),(37,36,101);

查询：

    DECLARE @pJob VARCHAR(Max)

SET @pJob = '101'

DECLARE @pWorkOrder VARCHAR(6)

SET @pWorkOrder = '1'

DECLARE @WOList1 TABLE (
    Job VARCHAR(12)
    ,WorkOrder VARCHAR(12)
    ,ParentWorkOrder VARCHAR(12)
    )
DECLARE @WOList2 TABLE (
    Job VARCHAR(12)
    ,WorkOrder VARCHAR(12)
    ,SectorWO VARCHAR(12)
    )

INSERT INTO @WOList1 (
    Job
    ,WorkOrder
    ,ParentWorkOrder
    )
SELECT Job
    ,WorkOrder
    ,ParentWorkOrder
FROM WOMaster
WHERE Job = @pJob
    AND ParentWorkorder <> WorkOrder;

WITH cte
AS (
    SELECT WO1.WorkOrder
        ,WO1.ParentWorkOrder
    FROM @WOList1 WO1

    UNION ALL

    SELECT c.WorkOrder
        ,WO1.ParentWorkOrder
    FROM @WOList1 WO1
    INNER JOIN cte c ON c.ParentWorkOrder = WO1.WorkOrder
    )
INSERT INTO @WOList2 (
    Job
    ,WorkOrder
    ,SectorWO
    )
SELECT WO1.Job
    ,C.WorkOrder
    ,C.ParentWorkOrder
FROM CTE C
LEFT JOIN @WOList1 WO1 ON C.WorkOrder = WO1.WorkOrder
WHERE C.ParentWorkOrder IN (
        SELECT WorkOrder
        FROM @WOList1
        WHERE ParentWorkOrder = @pWorkOrder
        )

预期产出：

Job WorkOrder   SectorWO
101 2   2
101 3   2
101 4   2
101 5   2
101 6   2
101 7   2
101 8   2
101 9   2
101 10  2
101 11  2
101 16  2
101 12  12
101 13  12
101 14  12
101 15  12
101 17  17
101 18  17
101 19  17
101 20  20
101 21  21
101 22  21
101 23  21
101 24  21
101 25  21
101 26  21
101 27  27
101 28  27
101 29  27
101 30  30
101 31  30
101 32  30
101 33  30
101 34  34
101 35  34
101 36  34
101 37  34

Answer 1

您还没有举例说明您想要输出的样子。所以这是我最好的尝试。我认为你可能会使这比必要的更复杂。

SELECT subwo.job, subwo.workorder SubWO, secondsubwo.workorder SecondSubWO
FROM WOMaster
LEFT JOIN WOMaster SubWO ON Subwo.parentworkorder = womaster.workorder
LEFT JOIN WOMaster SecondSubWo ON SecondSubWo.parentworkorder = Subwo.workorder
WHERE WOMaster.parentworkorder IS NULL
ORDER BY cast(subwo.workorder AS INT), cast(secondsubWO.workorder AS INT)

现在您已经澄清了输出。我认为你应该使用递归公用表表达式来获得你想要的东西。

;
with woList as
(select toplevel.workorder, toplevel.job, toplevel.parentworkorder
, 1 as WOLevel
From womaster toplevel
UNION ALL
SELECT wo.workorder, wo.job, wo.parentworkorder
, wolist.wolevel+1 as wolevel
FROM womaster wo
INNER JOIN wolist on wo.parentworkorder=wolist.workorder
WHERE wo.parentworkorder is not null)

select 
WoMaster.job, WoMaster.workorder, sector.workorder SectorWO
 from womaster womaster
 inner join wolist sector on sector.workorder=womaster.parentworkorder
 where wolevel=2
UNION ALL 
Select sector2.job, sector2.workorder, sector2.workorder
FROM wolist sector2
where wolevel=2
 order by cast(womaster.job as int), cast(sector.workorder as int), cast(womaster.workorder as int)

Pinal Dave explains this really well.

SQL分层查询 - 多个层，只关心一个

1 个答案: