Question

我有一张表可以返回如下记录：

Name   Total_Case_Count   User_Case_Count   P_Count  Rej_Count  PPP_Count    Other_Count

ABC        20                  10            03
ABC        20                  10                      05 
ABC        20                  10                                 02 
XYZ        20                  10            05
XYZ        20                  10                      02
XYZ        20                  10                                 01
XYZ        20                  10                                             02

但我需要这样的结果：

 Name   Total_Case_Count   User_Case_Count   P_Count  Rej_Count  PPP_Count    Other_Count

 ABC        20                  10            03           05       02
 XYZ        20                  10            05           02       01        02

表示用户数和＆amp;的总和其他计数将在同一行。我正在使用此查询：

    select distinct result.NAME, result.USER_ACCOUNT_ID,Total_Case_Count,User_Case_COUNT,Pending_Case_Count,
            Rejected_Case_Count,Pending_For_Payment_Case_Count,Active_Case_Count FROM
(
select row_number() over (order by C.CASE_ID asc) as row_index,
   UA.USER_ACCOUNT_ID,
   UA.FIRST_NAME ||' '||UA.LAST_NAME AS NAME,
   COUNT(*) OVER () Total_Case_Count,
   COUNT(*) OVER (PARTITION BY UA.USER_ACCOUNT_ID) User_Case_COUNT,

   CASE 
            WHEN C.CASE_STATUS_ID = 2 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Pending_Case_Count,
   CASE 
            WHEN C.CASE_STATUS_ID = 4 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Rejected_Case_Count,
   CASE 
            WHEN C.CASE_STATUS_ID = 6 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Pending_For_Payment_Case_Count,
   CASE 
            WHEN C.CASE_STATUS_ID In (1,3,5,7,8,9) THEN  COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Active_Case_Count
FROM CASE C 
INNER JOIN CASE_STATUS CS ON CS.CASE_STATUS_ID = C.CASE_STATUS_ID
INNER JOIN SSO.USER_ACCOUNTS UA ON UA.USER_ACCOUNT_ID = C.CREATED_BY 
inner join sso.User_In_Types uit on uit.USER_ACCOUNT_ID = UA.USER_ACCOUNT_ID 
inner join SSO.USER_TYPES  ut on UT.USER_TYPE_ID = UiT.USER_TYPE_ID 
where UT.APPLICATION_ID = 12 and UT.USER_TYPE_ID = 2170
) result 
ORDER BY NAME

任何建议都非常感谢..

Answer 1

您可以在外部select中使用聚合：

select result.NAME, result.USER_ACCOUNT_ID,MAX(Total_Case_Count),MAX(User_Case_COUNT),MAX(Pending_Case_Count),
            MAX(Rejected_Case_Count),MAX(Pending_For_Payment_Case_Count),MAX(Active_Case_Count) FROM
(
select row_number() over (order by C.CASE_ID asc) as row_index,
   UA.USER_ACCOUNT_ID,
   UA.FIRST_NAME ||' '||UA.LAST_NAME AS NAME,
   COUNT(*) OVER () Total_Case_Count,
   COUNT(*) OVER (PARTITION BY UA.USER_ACCOUNT_ID) User_Case_COUNT,

   CASE 
            WHEN C.CASE_STATUS_ID = 2 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Pending_Case_Count,
   CASE 
            WHEN C.CASE_STATUS_ID = 4 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Rejected_Case_Count,
   CASE 
            WHEN C.CASE_STATUS_ID = 6 THEN COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Pending_For_Payment_Case_Count,
   CASE 
            WHEN C.CASE_STATUS_ID In (1,3,5,7,8,9) THEN  COUNT(*) OVER (PARTITION BY C.CASE_STATUS_ID,UA.USER_ACCOUNT_ID) end as Active_Case_Count
FROM CASE C 
INNER JOIN CASE_STATUS CS ON CS.CASE_STATUS_ID = C.CASE_STATUS_ID
INNER JOIN SSO.USER_ACCOUNTS UA ON UA.USER_ACCOUNT_ID = C.CREATED_BY 
inner join sso.User_In_Types uit on uit.USER_ACCOUNT_ID = UA.USER_ACCOUNT_ID 
inner join SSO.USER_TYPES  ut on UT.USER_TYPE_ID = UiT.USER_TYPE_ID 
where UT.APPLICATION_ID = 12 and UT.USER_TYPE_ID = 2170
) result 
GROUP BY result.NAME, result.USER_ACCOUNT_ID
ORDER BY NAME

Answer 2

我不确定我是否完全理解您的问题，但您不能只使用group by吗？

SELECT Name
      ,Total_Case_Count
      ,SUM(User_Case_Count)
      ,SUM(P_Count)
      ,SUM(Rej_Count)          
      ,SUM(PPP_Count)
      ,SUM(Other_Count)
FROM (Your table Here)
GROUP BY Name
        ,Total_Case_Count

Answer 3

我想你需要简单的Group by和Aggregate

SELECT Name,
       Total_Case_Count,
       User_Case_Count,
       Max(P_Count),
       Max(Rej_Count),
       Max(PPP_Count),
       Max(Other_Count)
FROM   Yourtable
GROUP  BY Name,
          Total_Case_Count,
          User_Case_Count

分析查询

3 个答案: