Question

我有以下数据

PROD_NO    PROD_CAT     PROD_DESCRIPTION
X23        PENS          N/A
X23        PENCIL        in warehouse
X23        INK           "
X30        BOOKS         "
X30        DRAWINGS      not in warehouse
X30        ERASERS       "

我想要实现的是，如果PROD_DESCRIPTION有N / A或＆＃34;，那么我希望那些行被填充注释存在对于那个prod_no。例如仓库中的X23 将为所有行填充。对于所有行填写X30 不在仓库。

PROD_NO    PROD_CAT     PROD_DESCRIPTION
X23        PENS          in warehouse
X23        PENCIL        in warehouse
X23        INK           in warehouse
X30        BOOKS         not in warehouse
X30        DRAWINGS      not in warehouse
X30        ERASERS       not in warehouse

我该怎么做？每个prod_no都有很多prod_no和prod_description不同

Answer 1

试试这个并告诉我

Out-file $logfile -append

或

这也应该有用。

UPDATE YOUR_TABLE SET PROD_DESCRIPTION=decode(PROD_NO,'X23','in warehouse','X30','not in warehouse') WHERE PROD_DESCRIPTION='N/A' or PROD_DESCRIPTION=''

<强>被修改

假设所有生产没有两种类型的描述。相应地传递UPDATE YOUR_TABLE SET PROD_DESCRIPTION= CASE WHEN PROD_NO='X23' THEN 'in warehouse' WHEN PROD_NO='X30' THEN 'not in warehouse' END WHERE PROD_DESCRIPTION IN('N/A','')中的所有prod_no。

IN()

Answer 2

试试这个：

select prod_no
     , prod_cat 
     , case when prod_no = 'X23' 
       then 'in warehouse' 
       else 'not in warehouse' end as prod_description 
from [your_table_name]

Answer 3

UPDATE [YourTable]
SET PROD_DESCRIPTION = 
( CASE  
WHEN (PROD_DESCRIPTION = N/A and PROD_NO = X23) THEN 'in warehouse' 
WHEN (PROD_DESCRIPTION = "" and PROD_NO = X23) THEN 'in warehouse' 
WHEN (PROD_DESCRIPTION = N/A and PROD_NO = X30) THEN 'not in warehouse' 
WHEN (PROD_DESCRIPTION = "" and PROD_NO = X30) THEN 'not in warehouse' 
ELSE  (PROD_DESCRIPTION)
END )

Answer 4

SELECT使用相关的子查询：

select t1.PROD_NO,
       t1.PROD_CAT     
       (select max(t2.PROD_DESCRIPTION)
        from tablename t2
        where t2.PROD_NO = t1.PROD_NO
          and t2.PROD_DESCRIPTION <> 'N/A'
          and t2.PROD_DESCRIPTION <> ''),
from tablename t1

JOIN版本，GROUP BY找不到仓库＆＃39;或者＆＃39;在仓库＆＃39;：

select t1.PROD_NO,
       t1.PROD_CAT,
       t2.PROD_DESCRIPTION
from tablename t1
LEFT JOIN (select PROD_NO, max(PROD_DESCRIPTION)
           from tablename
           where PROD_DESCRIPTION <> 'N/A'
             and PROD_DESCRIPTION <> ''
           group by PROD_NO) t2
    ON t1.PROD_NO = t2.PROD_NO

如果prod_no在仓库中同时拥有＆＃39;＆＃39;并且＆＃39;不在仓库中，MAX将返回＆＃39;不在仓库＆＃39;作为价值。如果你想要在仓库里＆＃39;相反，切换到子选择中的min(t2.PROD_DESCRIPTION)。

Answer 5

我认为这会有所帮助：）

SELECT P.PROD_NO,P.PROD_CAT,(SELECT PROD_DESCRIPTION FROM PRODUCT WHERE
PROD_DESCRIPTION NOT IN ('"','N/A') AND  PROD_NO = P.PROD_NO limit 1 ) 
AS DESCRIPTION  FROM PRODUCT P

我使用内部查询，因为我认为单个产品可能有多个描述，而不是'“'或'N / A'”如果情况并非如此，那么你可以使用这个

 SELECT P.PROD_NO,P.PROD_CAT, P1.PROD_DESCRIPTION FROM PRODUCT P
 JOIN PRODUCT P1 ON P.PROD_NO = P1.PROD_NO 
 WHERE P1.PROD_DESCRIPTION NOT IN ('"','N/A')

Answer 6

您应为每个PROD_NO创建一个包含MAXIMUM PROD_DESCRIPTION的JOIN表，然后使用DECODE将此值输出为NULL，''或'N / A'：

SELECT T.PROD_NO,
       T.PROD_CAT,
       DECODE (T.PROD_DESCRIPTION, NULL,TMAX.PROD_DESC_MAX, 
                                     '',TMAX.PROD_DESC_MAX,
                                  'N/A',TMAX.PROD_DESC_MAX,
                                        T.PROD_DESCRIPTION) 
       PROD_DESCRIPTION
FROM T
LEFT JOIN (SELECT PROD_NO, 
                  MAX(PROD_DESCRIPTION) PROD_DESC_MAX
            FROM T GROUP BY PROD_NO) TMAX
     ON T.PROD_NO = TMAX.PROD_NO

SQLFiddle demo

根据条件填写的列

6 个答案: