didReceiveRemoteNotification不叫Swift

Question

出于某种原因，我的didReceiveRemoteNotification永远不会被调用。我做了以下事情：

APNS清单：

使用推送通知

创建允许的AppId

使用有效证书和应用ID

创建SSL证书

使用相同的证书创建配置文件，并确保添加设备

使用代码：

注册推送通知的应用

处理didRegisterForRemoteNotificationsWithDeviceToken方法

设定目标＆gt;能力＆GT;背景模式＆gt;远程通知 处理didReceiveRemoteNotification

但我的功能似乎没有被调用。我的代码如下所示：

  func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
    // Override point for customization after application launch.

    if (application.respondsToSelector("isRegisteredForRemoteNotifications"))
    {
        // iOS 8 Notifications
        application.registerUserNotificationSettings(UIUserNotificationSettings(forTypes: (.Badge | .Sound | .Alert), categories: nil));
        application.registerForRemoteNotifications()
    }
    else
    {
        // iOS < 8 Notifications
        application.registerForRemoteNotificationTypes(.Badge | .Sound | .Alert)
    }


    return true
}


func application(application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: NSData) {
    let tokenChars = UnsafePointer<CChar>(deviceToken.bytes)
    var tokenString = ""

    for var i = 0; i < deviceToken.length; i++ {
        tokenString += String(format: "%02.2hhx", arguments: [tokenChars[i]])
    }

    apnsID = tokenString
    println("******apnsID is \(apnsID)")
    dToken = deviceToken
    println("******dToken is \(dToken)")
    NSUserDefaults.standardUserDefaults().setObject(deviceToken, forKey: "deviceToken")
}

func application(application: UIApplication, didFailToRegisterForRemoteNotificationsWithError error: NSError) {
    println("***********didFailToRegisterForRemoteNotificationsWithError")
    println(error)
}

func application(application: UIApplication, didReceiveRemoteNotification userInfo: [NSObject : AnyObject], fetchCompletionHandler completionHandler: (UIBackgroundFetchResult) -> Void) {

    println("Getting notification")

    var message: NSString = ""
    var alert: AnyObject? = userInfo["aps"]

    println(userInfo["aps"])

    if((alert) != nil){
        var alert = UIAlertView()
        alert.title = "Title"
        alert.message = "Message"
        alert.addButtonWithTitle("OK")
        alert.show()
    }

}

Answer 1

我发现自己也遇到了同样的问题，为了调用didReceiveRemoteNotification，传入的通知音乐带有一个"available_content" : true参数和通知有效载荷。因此，如果您以字典形式发送通知，就像我在设备到设备推送中的情况一样，只需将其添加到字典中，就像您为sound或{{ 1}}，如果您将某种推送服务用作Postman，则也需要

Answer 2

三个步骤：

1. 在此处添加处理传入通知的逻辑：

   func application(_ application: UIApplication, didReceiveRemoteNotification userInfo: [AnyHashable: Any], fetchCompletionHandler completionHandler: @escaping (UIBackgroundFetchResult) -> Void) { // 在此处添加您的逻辑

completionHandler(.newData)

}

2. 为目标中的功能添加后台模式，并确保选中“远程通知”

3. 在发送推送通知时，添加 "content_available" : true

这在 iOS 14/Xcode 12.3 中对我有用。