Question

我没有理解某些行为，并希望有人在这里解释它。如果我运行Neo4j查询：

MATCH (node1-[:depends*]->node2) 
WITH [node1.name, node2.name] as dependencies
return dependencies

我得到了node1的元组列表，node2显示了node1在图中某处依赖于node2的所有元组。

如果我执行以下查询，我希望返回依赖项中的所有元组，但我得到一个空列表：

MATCH (node1-[:depends*]->node2) 
WITH [node1.name, node2.name] as dependencies
return dependencies
MATCH n1--n2
WHERE ([n1.name,n2.name] IN dependencies)
return n1,n2

现在我如何在子查询中使用依赖项？

Answer 1

多个var modules = new List<Module>() { new Module() { Id = 1, ModuleName = "Contabilidad", FontAwesomeClass = "fa-ambulance" }, new Module() { Id = 2, ModuleName = "Recursos Humanos", FontAwesomeClass = "fa-heartbeat" }, new Module() { Id = 3, ModuleName = "Inventario", FontAwesomeClass = "fa-anchor" }, new Module() { Id = 4, ModuleName = "Produccion", FontAwesomeClass = "fa-binoculars" }, new Module() { Id = 6, ModuleName = "Ventas", FontAwesomeClass = "fa-coffee" }, new Module() { Id = 7, ModuleName = "Compras", FontAwesomeClass = "fa-calendar-o" }, new Module() { Id = 8, ModuleName = "Cotizaciones", FontAwesomeClass = "fa-building" } }; context.ModulosPorUsuario.Add(new ModulosPorUsuario() { Email = "companyadmin@xx.onmicrosoft.com", Modules = modules }); context.SaveChanges();子句可以在同一个查询中互相关联，因此这可能对您有用：

MATCH

在WHERE ... IN中使用元组

1 个答案: