我试图通过此代码获取Mac地址:
void getMacAdress(unsigned char **address)
{
int s;
struct ifreq buffer;
s = socket(PF_INET, SOCK_DGRAM, 0);
memset(&buffer, 0x00, sizeof(buffer));
strcpy(buffer.ifr_name, "eth0");
ioctl(s, SIOCGIFHWADDR, &buffer);
close(s);
*address = (unsigned char *)buffer.ifr_hwaddr.sa_data;
for (s = 0; s < 6; s++)
{
printf("%.2X ", *(*address + s));
}
printf("\n");
}
int main(int argc, char *argv[])
{
unsigned char *address;
getMacAdress(&address);
int i;
for (i = 0; i < 6; i++)
{
printf("%.2X ", *(address + i));
}
printf("\n");
return 0;
}
我得到了正确的结果
08 00 27 0A 4E 98
08 00 27 0A 4E 98
但是当我在printf
函数中删除getMacAddress()
代码段时,它变为:
void getMacAdress(unsigned char **address)
{
int s;
struct ifreq buffer;
s = socket(PF_INET, SOCK_DGRAM, 0);
memset(&buffer, 0x00, sizeof(buffer));
strcpy(buffer.ifr_name, "eth0");
ioctl(s, SIOCGIFHWADDR, &buffer);
close(s);
*address = (unsigned char *)buffer.ifr_hwaddr.sa_data;
printf("\n");
}
我得错了结果
08 00 00 00 00 00
你能解释一下为什么会这样,以及如何解决这个问题?
答案 0 :(得分:3)
问题出在这里:
*address = (unsigned char *)buffer.ifr_hwaddr.sa_data;
buffer
是函数的局部变量。因此,您在address
中存储的指针指向一个局部变量,该函数在函数返回时被销毁,留下一个悬空指针。
尝试从此指针读取会导致未定义的行为。您可以根据打印时是否已将内存重新用于其他内容来解释您的输出。
答案 1 :(得分:2)
如果你想解决它......
[['610.0', '1150.0'],['675', '1150'],['675', '1215'],['610', '1215'],['610', '1150']]
答案 2 :(得分:1)
您不能指向要在函数中返回的堆栈空间。
相反,您可以使用malloc堆空间来存储所需的结果:
void getMacAdress(unsigned char **address)
{
int s;
struct ifreq buffer;
s = socket(PF_INET, SOCK_DGRAM, 0);
memset(&buffer, 0x00, sizeof(buffer));
strcpy(buffer.ifr_name, "eth0");
ioctl(s, SIOCGIFHWADDR, &buffer);
close(s);
*address = (unsigned char*) malloc(sizeof(buffer.ifr_hwaddr.sa_data));
memcpy(*address, buffer.ifr_hwaddr.sa_data,sizeof(buffer.ifr_hwaddr.sa_data));
//for (s = 0; s < 6; s++)
//{
// printf("%.2X ", *(*address + s));
//}
//printf("\n");
}
BTW,不要忘记释放主函数中的堆空间。