Question

我试图拆分以下分隔符：句号，分号，*，+ ,?而且 - 但是，我只想在句子开头出现时将“ - ”分开（以便不分割“非功能性”等词语

我尝试了以下但我没有取得任何进展，任何帮助将不胜感激：

sentences = re.split("[.-;]*[\+]*[\?]*[\*]*", txt)

这是我一直在尝试的示例文本：

- Text Editor: Now you can edit plain text files with airport tools
* Updated Dropbox support 
* Improved
stability
- New icon                                                                          
* See this case mis-alignment

拆分后的预期输出是项目列表：

TextEditor: Now you can edit plain text files with airport tools, Updated Dropbox support, Improved stability, New icon, See this case mis-alignment

Answer 1

尝试枚举这样的分隔符：

re.split（“[。; * +？]”）

Answer 2

如果你想在一组定义的分隔符中拆分字符串而不是这样：

>>> txt = '- Text Editor: Now you can edit plain text files with airport tools'
>>> r = re.split(r'([.;*+?-]+)',txt)
>>> r
['', '-', ' Text Editor: Now you can edit plain text files with airport tools']

如果您不希望在结果列表中输入分隔符：

>>> r = re.split(r'[.;*+?-]+',txt)
>>> r
['', ' Text Editor: Now you can edit plain text files with airport tools']

编辑：在回复您的以下评论时，请使用\s作为空格：

    >>> txt = '''- Text Editor: Now you can edit plain text files with airport tools
    * Updated Dropbox support 
    * Improved
    stability
    - New icon'''
     >>> r = re.split('(^|\s)+[.;*+?-]+($|\s)+',txt) 
     >>> [i for i in r if len(i) > 1]
['Text Editor: Now you can edit plain text files with airport tools', 'Updated Dropbox support', 'Improved\n    stability', 'New icon']

Answer 3

您可以使用此re.split功能。

>>> import re
>>> s = '''- Text Editor: Now you can edit plain text files with airport tools
* Updated Dropbox support 
* Improved
stability
- New icon'''
>>> [i for i in re.split(r'(?m)\s*^[-*+?]+\s*', s) if i]
['Text Editor: Now you can edit plain text files with airport tools', 'Updated Dropbox support', 'Improved\nstability', 'New icon']

正则表达式匹配多个分隔符

3 个答案: