Question

我有样本xelement：

<Books>
  <Book>
    <Id>123</Id>
    <EndDate>01/11/2009</EndDate>
    <Price>$0.00</Price>
    <tag1>0</tag1>
    <tag2>0</tag2>
   </Book>
   <Book>
    <Id>567</Id>
    <EndDate>01/01/2001</EndDate>
    <Price>$0.00</Price>
    <tag1>1</tag1>
     <tag2>2</tag2>
   </Book>
   <Book>
    <Id>567</Id>
    <EndDate>01/01/2001</EndDate>
     <tag1>22</tag1>
     <tag2>33</tag2>
    <Price>$0.00</Price>
    </Book>
</Books>

当enddates相同时，我必须合并2个节点（与coma分离）。对于上面的输入我不得不放弃。

<Books>
  <Book>
    <Id>123</Id>
    <EndDate>01/11/2009</EndDate>
    <Price>$0.00</Price>
    <tag1>0</tag1>
    <tag2>0</tag2>
   </Book>
   <Book>
    <Id>567</Id>
    <EndDate>01/01/2001</EndDate>
    <Price>$0.00</Price>
    <tag1>1,22</tag1>
     <tag2>2,33</tag2>
   </Book>
  </Books>

我尝试使用聚合函数，但我无法添加结束日期条件。

Answer 1

使用C＃进行谷歌XML序列化。

将xml文件反序列化为List作为示例。
您的逻辑“删除一些记录或创建新的合并列表”
将新列表序列化为xml文件

或

public class Book
{
  public int Id { get; set; }
  public Decimal Price { get; set; }
  public DateTime EndDate{ get; set; }
  public string tag1{ get; set; }
  public string tag1{ get; set; }
}
....

XDocument xmlDoc = XDocument.Load("Books.xml");
List<Book> BookList1=
  (from Book in xmlDoc.Descendants("Book")
   select new Tutorial
   {
     Id = tutorial.Element("Id").Value,
     Price = tutorial.Element("Price").Value,
     EndDate = DateTime.Parse(tutorial.Element("EndDate").Value),
     tag1= tutorial.Element("tag1").Value,
     tag2= tutorial.Element("tag2").Value
   }).ToList<Tutorial>();
....
var BookGroups = from g in  BookList1 group g by Id into g
select new{Key=g.Key,Books=g};

List<Book> BookList2= new List<Book>();
foreach(var g in BookGroups)
{ 
  Book book = new Book();
  book.Id=g.Key;
  foreach(var b in g.Books)
  {
// put your logic 
  if(b.Price > book.Price) book.Price =b.Price;
  if(b.EndDate > book.EndDate) book.EndDate =b.EndDate;
  book.tag1+=b.tag1+",";
  book.tag2+=b.tag2+",";
 }
 book.tag1= book.tag1.Trim(',');
 book.tag2= book.tag2.Trim(',');
 BookList2.add(book);
}

Answer 2

以下几行中的内容可能会让您开始（说明性而非生产质量）：

// XElement sourceElement contains the original "Books" element.

var matchingBookGroups = 
    from x in sourceElement.Elements("Book")
    group x by string.Format("{0}-{1}", x.Element("Id").Value, x.Element("EndDate").Value) into g
    select new { Key = g.Key, Values = g };

XElement result =
    new XElement("Books",
        from matchingBookElements in matchingBookGroups
        let firstMatchingBookElement = matchingBookElements.Values.First()
        select
            new XElement("Book",
                firstMatchingBookElement.Element("Id"),
                firstMatchingBookElement.Element("EndDate"),
                firstMatchingBookElement.Element("Price"),
                    new XElement("tag1", string.Join(",", matchingBookElements.Values.Elements("tag1").Select(x => x.Value).ToArray())),
                    new XElement("tag2", string.Join(",", matchingBookElements.Values.Elements("tag2").Select(x => x.Value).ToArray()))));

如何根据xelement中的条件合并元素？

2 个答案: