我有两个文件,我正在尝试根据第1列和第2列加入/合并。
INPUT1
22 42960000 rs149201999 A AC 100 PASS LDAF=0.0649;RSQ=0.8652;AN=2184;ERATE=0.0046;VT=SNP;AA=.;AVGPOST=0.9799;THETA=0.0149;SNPSOURCE=LOWCOV;AC=134;AF=0.06;ASN_AF=0.04;AMR_AF=0.05;AFR_AF=0.10;EUR_AF=0.06
输入2
22 42960000 . A AC . . ;AA=1;AFE=0.989691;ASNE=1;EUN=0.992509;AFW=1;MED=0.991071;LAT=1
输出
22 42960000 . A AC . . ;AA=1;AFE=0.989691;ASNE=1;EUN=0.992509;AFW=1;MED=0.991071;LAT=1;LDAF=0.0649;RSQ=0.8652;AN=2184;ERATE=0.0046;VT=SNP;AA=.;AVGPOST=0.9799;THETA=0.0149;SNPSOURCE=LOWCOV;AC=134;AF=0.06;ASN_AF=0.04;AMR_AF=0.05;AFR_AF=0.10;EUR_AF=0.06
注意每个列由制表符分隔。
答案 0 :(得分:0)
这应该有效:
s=%%%%%%
join -j1 -o1.1,1.2,1.3,1.4,1.5,1.6,1.7,2.7 <(sed "s/\t/$s/" input2) \
<(sed "s/\t/$s/" input1) \
| sed "s/$s/\t/;
s/\(=[^ ]*\) \([^ ]*=\)/\1;\2/;
s/ \+/\t/g"
答案 1 :(得分:0)
这是使用GNU awk
的一种方式:
awk 'FNR==NR { array[$1,$2]=$8; next } ($1,$2) in array { print $0 ";" array[$1,$2] }' input1 input2
结果:
22 42960000 . A AC . . ;AA=1;AFE=0.989691;ASNE=1;EUN=0.992509;AFW=1;MED=0.991071;LAT=1;LDAF=0.0649;RSQ=0.8652;AN=2184;ERATE=0.0046;VT=SNP;AA=.;AVGPOST=0.9799;THETA=0.0149;SNPSOURCE=LOWCOV;AC=134;AF=0.06;ASN_AF=0.04;AMR_AF=0.05;AFR_AF=0.10;EUR_AF=0.06