Question

我有3 NSMutableArray个相同的大小。他们是＆＃34;链接＆＃34;这意味着对于相应的索引，它们彼此相关。

tableData = [NSMutableArray arrayWithObjects:@"Egg Benedict", @"Mushroom Risotto", @"Full Breakfast", nil]

thumbnails = [NSMutableArray arrayWithObjects:@"egg_benedict.jpg", @"mushroom_risotto.jpg", @"full_breakfast.jpg",nil]

prepTime = [NSMutableArray arrayWithObjects:@"10min", @"15min", @"8min",nil]

这来自我正在玩的教程。

我正在过滤tableData数组，如下所示：

NSPredicate *resultPredicate = [NSPredicate
                                    predicateWithFormat:@"SELF contains[cd] %@",
                                    searchText];

searchResultsData = [[tableData filteredArrayUsingPredicate:resultPredicate] mutableCopy];

其中searchText是包含过滤器的字符串（例如＆＃34; egg＆＃34;）。这很好用，我的意思是我有正确的过滤。（searchResultsData是另一个NSMutableArray）我需要做的是根据从上面NSMutableArray获得的结果过滤其他两个NSPredicate。

所以我创建了另外两个NSMutableArray s，名为＆＃34; searchResultThumbnails＆＃34;和＆＃34; searchResultPrepTime＆＃34;。我期待这个：如果我过滤使用＆＃34; egg＆＃34;我想要第一个元素包含＆＃34; egg＆＃34;来自＆＃34; tableData＆＃34;数组（在这种情况下只有一个元素）和缩略图和预处理数组中索引处的对应元素。

用＆＃34; Egg＆＃34;过滤后结果应该是：

searchResultData = "Egg"
searchResultThumbnails = "egg_benedict.jpg"
searchResultPrepTime = "10min"

感谢您的帮助。

Answer 1

相信“他们是”联系在一起的“这意味着对于相应的索引，他们有相互关联的东西。”作为你的情况

NSPredicate *resultPredicate = [NSPredicate
                                predicateWithFormat:@"SELF contains[cd] %@",
                                searchText];

searchResultsData = [[tableData filteredArrayUsingPredicate:resultPredicate] mutableCopy];
NSString *searchedText = [searchResultsData objectAtIndex:0];
NSInteger index = [tableData indexOfObject:searchedText]; //if searchedText = "Egg"
NSString *thumb = [thumbnails objectAtIndex:index];
NSString *prep= [prepTime objectAtIndex:index];

但这不是更好的方法。

你有很多选择您可以使用可能具有属性项，缩略图，prepTime的自定义类。

您还可以使用类似于以下格式的词典数组

 array = (
          {
             searchResultData = "Egg"
             searchResultThumbnails = "egg_benedict.jpg"
             searchResultPrepTime = "10min"
          }
          {
             searchResultData = "someItem"
             searchResultThumbnails = "some.jpg"
             searchResultPrepTime = "10min"
          }
        )

Answer 2

试试这个：

NSArray* tableData = [NSMutableArray arrayWithObjects:@"Egg Benedict", @"Mushroom Risotto", @"Full Breakfast", nil];

NSArray* thumbnails = [NSMutableArray arrayWithObjects:@"egg_benedict.jpg", @"mushroom_risotto.jpg", @"full_breakfast.jpg",nil];

NSArray* prepTime = [NSMutableArray arrayWithObjects:@"10min", @"15min", @"8min",nil];

NSMutableArray *storedIndex = [NSMutableArray arrayWithCapacity:tableData.count];
for (NSUInteger i = 0 ; i != tableData.count ; i++) {
    [storedIndex addObject:[NSNumber numberWithInteger:i]];
}

//Now you are going to sort tabledata.. with it we will sort storedIndexs
//suppose we will compare the strings for this time
[storedIndex sortUsingComparator:^NSComparisonResult(id obj1, id obj2){

NSString *lhs = [[tableData objectAtIndex:[obj1 intValue]] lowercaseString];
NSString *rhs = [[tableData objectAtIndex:[obj2 intValue]] lowercaseString];
return [lhs compare:rhs];
}];     //now storedIndex are sorted according to sorted tableData array

NSMutableArray *sortedTableData = [NSMutableArray arrayWithCapacity:tableData.count];
NSMutableArray *sortedThumbnail = [NSMutableArray arrayWithCapacity:tableData.count];
NSMutableArray *sortedPrepTime = [NSMutableArray arrayWithCapacity:tableData.count];

[p enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
    NSUInteger pos = [obj intValue];
    [sortedTableData addObject:[tableData objectAtIndex:pos]];
    [sortedThumbnail addObject:[thumbnails objectAtIndex:pos]];
    [sortedPrepTime addObject:[prepTime objectAtIndex:pos]];
}];

//Now all will be correct index relation to each other as previous

它会完美运作。快乐的编码。：）

在过滤另一个NSMutableArray的基础上过滤NSMutableArray

2 个答案: