Question

我有一个问题，所以我有两张桌子：

订单：

id   supplier_id    status
1    2              3
2    4              5
3    2              7

gift_2_order：

order_id  gift_id  order_price
1         2        4
2         1        5
3         2        6
1         6        1
2         4        9

所以我想获得所有订单，在表格中重复多少次：gift_2_order和total price。对于这个例子，我想得到：

order    number_repetitions      total_price
1        2                        5
2        2                        14
3        1                        6

我试过了：

SELECT
    ord.estimation_date,
    ord.order_date,
    ord.supplier_id,
    ord.status,
    count.(g2o.order_id),
    sum.(g2o.order_price)
FROM `order` ord
INNER JOIN gift_2_order g2o on ord.id = g2o.order_id

你能帮帮我吗？提前谢谢。

Answer 1

您必须按ord.id分组并从.

中删除count and sum

         SELECT
                ord.id,
                count(g2o.order_id),
                sum(g2o.order_price)
            FROM `order` ord
            INNER JOIN gift_2_order g2o on ord.id = g2o.order_id
         group by ord.id order by ord.id

Answer 2

尝试：

    SELECT
    ord.order_id,
    count(g2o.order_id) as number_repetitions      ,
    sum(g2o.order_price) as total_price
    FROM `order` ord
    INNER JOIN gift_2_order g2o on ord.id = g2o.order_id
   group by ord.order_id

顺便说一句＆＃34;顺序＆＃34;是不是很好的表名。

Answer 3

SELECT
    t1.supplier_id,
    t1.status,
    count(t2.order_id) as total_orders,
    sum(t2.order_price) as total_amount
FROM `order` t1
join gift_2_order t2 where t1.id = t2.order_id group by t2.order_id

Answer 4

你不需要做一个JOIN。没有JOIN，查询将更具性能......

这个SQL小提琴会让你感到兴奋：

SELECT
    order_id,
    count(order_id),
    sum(order_price)
FROM gift_2_order
GROUP BY order_id
ORDER BY order_id

如果您不需要加入表格，请不要这样做。

从具有多个条件的2个表中检索数据

4 个答案: