Question

我需要一个SQL查询，从2个表中选择多个条件。

table1
order_row | timestamp |
-----------------------
0001      |2016-11-04 |
0002      |2016-11-04 |
0003      |2016-11-04 |
0004      |2016-11-03 |
0006      |2016-11-03 |

table2
order_row | timestamp |
-----------------------
0001      |2016-11-05 |
0002      |2016-11-04 |
0003      |2016-11-04 |
0004      |2016-11-04 |
0005      |2016-11-04 |
0006      |2016-11-02 |

我希望获取所有行，以便从order_row获取所有table2行，而table1和order_row行中不包含table2行时间戳在table2中比table1更新。并且仅比2016-11-03更新table 2 timestamp的行结果必须是：

order_row | 
----------
0001      | because timestamp is newer in table2
0004      | because timestamp is newer in table2
0005      | because it's not present in table1

Answer 1

这应该这样做：

SELECT t2.*
FROM Table2 AS t2
LEFT JOIN Table1 AS t1 
   ON t2.order_row = t1.order_row 
WHERE t1.order_row IS NULL OR t2.`timestamp` > t1.`timestamp`

Demo here

修改：如果您只想要考虑table2之前'2016-11-03'以上的记录，则只需添加：

t2.`timestamp` > '2016-11-03' AND ( ... other conditions here ...)

从2个有条件的表中选择

1 个答案: