R barplot - 排序后保持相同的颜色

时间:2015-06-24 13:58:26

标签: r sorting plot bar-chart

我想将3个变量(a,b,c)的百分比一个接一个地绘制出来。因此,对于变量 a b c 的一组活动,我有一个矩阵(%)。

dta = structure(c(0.0073, 0.1467, 0.0111, 0.0294, 0.0451, 0.0031, 0.1823, 
        0.0452, 0.2212, 0.1123, 7e-04, 0.1138, 0.0723, 0.1649, 0.0634), 
        .Dim = c(5L, 3L), 
        .Dimnames = list(c("c Work", "e Travel/Commute", 
                           "f Cooking", "g Housework", "h Odd jobs"),
                         c("a", "b", "c")))

但是,我想绘制每个变量的排序,但为活动集保持相同的颜色。

所以这是活动的颜色。

library(RColorBrewer) 

rc = c(brewer.pal(n = 5, name = 'Set2'))  

kol = list()
kol$act <- c("c Work", "e Travel/Commute", "f Cooking", "g Housework", "h Odd jobs" )
kol$colours <- rc
kol = as.data.frame(kol)

               act colours
1           c Work #66C2A5
2 e Travel/Commute #FC8D62
3        f Cooking #8DA0CB
4      g Housework #E78AC3
5       h Odd jobs #A6D854

所以这是我的条形图

par(mfrow = c(2,2))
barplot(dta[,1], horiz = T, las = 2, col = kol$colours)
barplot(dta[,2], horiz = T, las = 2, col = kol$colours)
barplot(dta[,3], horiz = T, las = 2, col = kol$colours)

所以我想要的是为活动保持相同的颜色

par(mfrow = c(2,2))
barplot(sort(dta[,1]), horiz = T, las = 2)
barplot(sort(dta[,2]), horiz = T, las = 2)
barplot(sort(dta[,3]), horiz = T, las = 2)

如何让它“匹配”?

1 个答案:

答案 0 :(得分:1)

您可以使用函数match来匹配“实体”的名称和所需的颜色,例如,第一列:

kol$colours[match(names(sort(dta[,1])), kol$act)]

所以,要获得你的条形图,只需:

par(mfrow = c(2,2), mar=c(5, 8, 4, 1)) # also modifying the margins to make the names fit in
for (i in 1:3) {
    barplot(sort(dta[,i]), horiz = T, las = 2, col=kol$colours[match(names(sort(dta[, i])), kol$act)])
}

enter image description here