我正在研究在学校项目中使用的应用程序。这是一个将文件上传到服务器的POC。但是,当我尝试上传文件时,此行会引发异常:
new diskfileitemfactory())。parserequest(request);
这是我的代码:
import java.io.File;
import java.io.IOException;
import java.util.List;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
/**
* Servlet to handle File upload request from Client
* @author Javin Paul
*/
public class FileUploadHandler extends HttpServlet {
private final String UPLOAD_DIRECTORY = "C:/uploads";
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
//process only if its multipart content
if(ServletFileUpload.isMultipartContent(request)){
try {
List<FileItem> multiparts = new ServletFileUpload(
new DiskFileItemFactory()).parseRequest(request);
//this is the problematic line^
for(FileItem item : multiparts){
if(!item.isFormField()){
String name = new File(item.getName()).getName();
item.write( new File(UPLOAD_DIRECTORY + File.separator + name));
}
}
//File uploaded successfully
request.setAttribute("message", "File Uploaded Successfully");
} catch (Exception ex) {
request.setAttribute("message", "File Upload Failed due to " + ex);
}
}else{
request.setAttribute("message",
"Sorry this Servlet only handles file upload request");
}
request.getRequestDispatcher("/result.jsp").forward(request, response);
}
}
我看到显示JSP代码是值得赞赏的:
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>File Upload Example in JSP and Servlet - Java web application</title>
</head>
<body>
<div>
<h3> Choose File to Upload in Server </h3>
<form action="upload" method="post" enctype="multipart/form-data">
<input type="file" name="file" />
<input type="submit" value="upload" />
</form>
</div>
</body>
</html>
答案 0 :(得分:0)
尝试此代码,可能对您有所帮助。
DiskFileItemFactory factory = new DiskFileItemFactory();
factory.setSizeThreshold(MEMORY_THRESHOLD);
factory.setRepository(new File(System.getProperty("java.io.tmpdir")));
ServletFileUpload upload = new ServletFileUpload(factory);
upload.setFileSizeMax(MAX_FILE_SIZE);
upload.setSizeMax(MAX_REQUEST_SIZE); // sets maximum size of request (include file + form data)
String uploadPath = getServletContext().getRealPath("") + File.separator + UPLOAD_DIRECTORY;
File uploadDir = new File(uploadPath);
if (!uploadDir.exists()) {
uploadDir.mkdir();
}
List<FileItem> multiparts= upload.parseRequest(request);