我有这样的查询:
declare @currentDate datetime,@enddate datetime;
set @currentDate = '06/1/2015';
select @enddate='06/05/2015'
while @currentDate < @enddate
begin
select @currentDate = dateadd(DAY,1,@currentDate);
select @currentDate as currentdate
end
但是在结果集中这没有显示我当前的日期。在s显示2015-06-02关于病房的日期..我想要包括我当前的日期
答案 0 :(得分:1)
这就是我的意思:
declare @currentDate datetime,@enddate datetime
set @currentDate = '20150601'
set @enddate='20150605'
while (@currentDate <= @enddate) begin
select @currentDate as currentdate
select @currentDate = dateadd(DAY,1,@currentDate)
end
答案 1 :(得分:0)
你在while循环中做的第一件事是增量currentDate。这将立即从2015年6月1日到2015年6月6日将其移至:
declare @currentDate datetime,@enddate datetime;
set @currentDate = '06/1/2015';
select @enddate='06/05/2015'
while @currentDate < @enddate --- May need to be <= if inclusive range.
begin
--- Do stuff with currentDate here THEN increment at the very end.
set @currentDate = dateadd(DAY,1,@currentDate);
end