Question

如何通过OpenCV Hough Circle Transformation获得准确的中心点？我需要在x，y坐标中有更多精确的小数位。

（准确地说，我的意思是这样的）我用matlab获得了这些中心坐标

x107,775526315904   y112,963480232638
x469,550463441518   y208,309866770404
x217,386414755458   y490,882895036058

这是我的代码：

#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <opencv2/core/core.hpp>
#include <iostream>
#include <stdio.h>

using namespace cv;
using namespace std;


int main()
{
    Mat src, src_gray, src0;
    printf("Give the name of the picture\n");
    char ImageName[20];
    scanf("%s", &ImageName);
    /// Read the image 
    src = imread(ImageName, 1);
    if (!src.data)
    {
        printf("no image data\n");
        return main();
    }
    // src0 = src;
    // imshow("orignal", src0);
    /// Convert it to gray
    cvtColor(src, src_gray, CV_BGR2GRAY);
    GaussianBlur(src_gray, src_gray, Size(9, 9), 2, 2);
    vector<Vec3f> circles;
    /// Apply the Hough Transform to find the circles
    HoughCircles(src_gray, circles, CV_HOUGH_GRADIENT, 0.92, src_gray.rows / 10, 20, 10, 55, 60);
    for (size_t i = 0; i < circles.size(); i++)
    {
        Point center(cvRound(circles[i][0]), cvRound(circles[i][1]));
        int radius = cvRound(circles[i][2]);
    //  printf("%d center x %d y %d\n", i, cvRound(circles[i][0]), cvRound(circles[i][1]));
    //  printf("rad: %d\n", cvRound(circles[i][2]));
        cout << i + 1 << " centerpoint " << " x: " << circles[i][0] << "   y: " << circles[i][1] << "rad: " << circles[i][2] << endl;
        // cout << i + 1 << " othermethod" << "x : " << center.x << endl;
        // circle center
        circle(src, center, 1, Scalar(0, 255, 0), -1, 8, 0);
        // circle outline
        circle(src, center, radius, Scalar(255, 0, 0), 1, 8, 0);
    }
    imshow("circlefinder", src);
    waitKey(1);
    system("PAUSE");
    cvDestroyWindow("orignal");
    cvDestroyWindow("circlefinder");
    printf("new picture ?(y/n)");
    char ans[1];
    scanf("%s", &ans);
    if (strcmp(ans, "y"))
    {
        return 0;
    }
    else if (strcmp(ans, "n"))
    {
        return main();
    }

}

这是输出：

Give the name of the picture
as2.jpg
145.5test x
1 centerpoint  x: 105.5   y: 112.5rad: 55.5563
2 centerpoint  x: 235.5   y: 427.5rad: 56.626
3 centerpoint  x: 466.5   y: 196.5rad: 55.5203
A folytatáshoz nyomjon meg egy billentyűt . . .
new picture ?

Answer 1

不是您的数据丢失了什么。这只是你跳过一些数字的打印功能。

尝试std :: setprecision：

std::cout << 432.123456789f << "   " << std::setprecision(10) << 432.123456789f << std::endl;

别忘了：

#include <iomanip>

无论如何，我认为你真的不需要这种精确性。图像处理中的度量误差通常很大，最后的数字不会给你任何真实的信息。

我怎样才能获得准确的中心点？

1 个答案: