Question

目前面临一个问题，如何将json格式的对象列表序列化为pojo。在我的作品中使用泽西休息服务它可以消耗json。如何使用具有对象数组的json对象反序列化rest请求。

json数组

{
    "subject": "hi",
    "description": [
        {
            "subject": "hi"
        },
        {
            "subject": "hi"
        }
    ]
}

我的pojo课程

public class t {

    private String subject;
    private List<t2> description;

    public String getSubject() {
        return subject;
    }

    public void setSubject(String subject) {
        this.subject = subject;
    }

    public List<t2> getDescription() {
        return description;
    }

    public void setDescription(List<t2> description) {
        this.description = description;
    }

}

t2.class

public class t2 {
    private String subject;

    public String getSubject() {
        return subject;
    }

    public void setSubject(String subject) {
        this.subject = subject;
    }
}

Answer 1

使用TypeReference。例如：

import java.io.IOException;

import com.fasterxml.jackson.core.JsonParseException;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.ObjectMapper;


public class JacksonParser {

    public static void main(String[] args) {
        t data = null;
        String json = "{\"subject\":\"hi\",\"description\":[{\"subject\":\"hi\"},{\"subject\":\"hi\"}]}";
        ObjectMapper mapper = new ObjectMapper();
        try {
            data = mapper.readValue(json, new TypeReference<t>() { });
        } catch (JsonParseException e) {
            System.out.println(e.getMessage());
        } catch (JsonMappingException e) {
            System.out.println(e.getMessage());
        } catch (IOException e) {
            System.out.println(e.getMessage());
        }
        System.out.println(data);
    }

}

反序列化jakson中对象的arrayList

1 个答案: