Question

以下是我正在使用的输出：

Pool Name:  Pool 2
Pool ID:  1
LUNs:  1015, 1080, 1034, 1016, 500, 1002, 1062, 1041, 1046, 1028, 1009, 1054, 513, 1058, 1070, 515, 1049, 1083, 1020, 1076, 19, 509, 1057, 1021, 525, 1019, 518, 1075, 29, 23, 1068, 37, 1064, 506, 1024, 1026, 1008, 1087, 1012, 1006, 1018, 502, 1004, 1074, 1030, 1032, 39, 1014, 1005, 1056, 1044, 2, 1033, 1001, 16, 1061, 1040, 1045, 1027, 26, 1023, 1053, 1037, 1079, 512, 520, 1069, 1039, 514, 1048, 1082, 523, 508, 524, 517, 522, 1066, 1089, 1067, 529, 528, 1063, 505, 1081, 527, 1007, 1086, 1051, 1011, 1035, 1017, 501, 1003, 1042, 1073, 1085, 1029, 1010, 24, 1013, 1055, 1043, 1059, 52, 1071, 516, 1050, 1084, 1000, 1077, 1060, 1072, 510, 1022, 1052, 526, 1036, 1078, 511, 35, 519, 1038, 521, 1047, 507, 6, 1065, 1025, 1088, 503, 53, 1031, 504

Pool Name:  Pool 1
Pool ID:  0
LUNs:  9, 3, 34, 10, 12, 8, 7, 0, 38, 27, 18, 4, 42, 21, 17, 28, 36, 22, 13, 5, 11, 25, 15, 32, 1

Pool Name:  Pool 4
Pool ID:  2
LUNs: (this one is empty)

我想要做的是存储每个＆＃34; LUN：＆＃34;进入自己的变量（数组？）。然后取我的号码并在所有阵列中搜索它，在这个例子中有三个。如果它匹配我的号码，例如＆＃34; 34＆＃34;该程序将输出Your number is in Pool 1

我知道如何使用Regex表达式拉出我需要的LUN行，我知道如何将结果与if语句进行比较，但是在考虑输出正确的＆＃34; Pool Name＆＃34;

修改的我应该添加可以更改的池总数以及LUN编号列表。

Answer 1

将输出转换为单个字符串，使用等号替换冒号并将字符串拆分为双换行符，然后使用$data = ... | Out-String $pools = $data -replace ': +','=' -split "`r`n`r`n" | % { New-Object -Type PSCustomObject -Property (ConvertFrom-StringData $_) } | select -Property *,@{n='LUNs';e={$_.LUNs -split ', '}} -Exclude LUNs和$pools | ? { $_.LUNs -contains 34 } | select -Expand 'Pool Name'将片段转换为对象，并将LUN字符串拆分为阵列：

Posts = TableEngine::Posts.dup

通过它，您可以获得包含给定LUN的池的池名称，如下所示：

Object.send :remove_const, :TableEngine

Answer 2

我确信有更简单的方法...... 这就是你需要的吗？

$Number = 42
$Lun1=1015, 1080, 1034, 1016, 500, 1002, 1062, 1041, 1046, 1028, 1009, 1054, 513, 1058, 1070
$Lun2=9, 3, 34, 10, 12, 8, 7, 0, 38, 27, 18, 4, 42, 21, 17, 28, 36, 22, 13, 5, 11, 25, 15, 32
$Lun3=$null
$Lun1Length=$Lun1.Length
$Lun2Length=$Lun2.Length
$Lun3Length=$Lun3.Length
[Array]$Luns = $Lun1, $Lun2, $Lun3
foreach ($Lun in $Luns)
{
    if ($Lun -contains $Number)
    {
      Switch ($Lun.Length)
      {
      $Lun1Length {"$Number in Lun1"}
      $Lun2Length {"$Number in Lun2"}
      $Lun3Length {"$Number in Lun3"}
      }
    } 
}

42 in Lun2

检查数字是否在多个字符串和标签中

2 个答案: