我已成功使用PDO
使用PDO::FETCH_OBJ
方法从我的数据库中获取数据,然后查询返回:
Array (
[0] => stdClass Object
(
[id] => 2
[title] => Johnny Sims
[img] =>
[description] =>
[school] =>
[location] => 1
[url] =>
[tablename] => 2
[votes] => 5
[name] => President Candidates
[Numopinions] => 6
)
[1] => stdClass Object
(
[id] => 2
[title] => Jeremy Pinto
[img] =>
[description] =>
[school] =>
[location] => 1
[url] =>
[tablename] => 2
[votes] => 4
[name] => Presidential Candidates
[Numopinions] => 6
)
[2] => stdClass Object
(
[id] => 2
[title] => Sarah Bushels
[img] =>
[description] =>
[school] =>
[location] => 1
[url] =>
[tablename] => 2
[votes] => 3
[name] => Presidential Candidates
[Numopinions] => 6
)
)
如果这是回显的话,如何使用AJAX
GET
请求与此数据进行交互?
答案 0 :(得分:1)
我假设您希望在JavaScript中与它进行交互,在这种情况下,您可以json_encode($array)
然后将其输出到内容类型标头设置为application / json的页面。
如果您随后使用AJAX请求该页面并将结果加载到var中,它将自动解析为JavaScript数组。
答案 1 :(得分:1)
这只是您的方案的一种表示。
的index.php
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title></title>
<!-- jQuery -->
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
</head>
<body>
<div id="result"></div>
<script>
$(document).ready(function(){
var userId= 1; //this can be anything like a gobal variable or an user input, etc
$.ajax({
url: "ajax.php",
type: "GET",
data: {id : userId}, //userId is the variable that you are going to pass to ajax.php
dataType: "json",
success: function(data) {
//your logic what do you want to do with it
$("#result").html( data.title + '-' + data.name);
},
error: function(xhr, textStatus, errorThrown) {
alert( "Request failed: " + textStatus );
}
})
});
</script>
</body>
</html>
ajax.php
<?php
//you logic here, this is just a dumy example
$id = isset($_GET['id']) ? $_GET['id'] : 0;
$db_records = array(
array(
"id" => 2,
"title" => 'Jeremy Pinto',
"img" => '',
"description" => '',
"school" => '',
"location" => 1,
"url" => '',
"tablename" => 2,
"votes" => 4,
"name" => 'Presidential Candidates',
"Numopinions" => 6
),
array (
"id" => 2,
"title" => 'Sarah Bushels',
"img" => '',
"description" => '',
"school" => '',
"location" => 1,
"url" => '',
"tablename" => 2,
"votes" => 3,
"name" => 'Presidential Candidates',
"Numopinions" => 6
)
);
print json_encode($db_records[$id]);