Question

我想从查询结果中显示一个下拉框但是我收到以下错误;在下拉框所在的位置，只有$ row显示没有实际内容

我的代码：

<?php
 $start=$_GET['arrival'];
 $end=$_GET['departure'];
 $type=$_GET['type'];

  $query = odbc_exec (odbc_connect("book", "", ""), "SELECT Location_id
  FROM PITCH
   WHERE (((PITCH.location_id) Not In (SELECT Location_Id FROM BOOKING
     WHERE StartDate OR EndDate 
     NOT BETWEEN
      #$start# -1  And #$end# +1)) AND ((PITCH.Type_name)='$type'))");
      $result = odbc_result_all($query);

       echo '<select name="type" id="type">
    While ($row = odbc_fetch_array ($result))

      {
         <option> $row </option>
     }
       </select>';

  ?>

Answer 1

以下是您的代码的样子：

<?php
$start     = isset($_GET['arrival']) ? trim($_GET['arrival']):null;
$end       = isset($_GET['departure']) ? trim($_GET['departure']):null;
$type      = isset($_GET['type']) ? trim($_GET['type']):null;

$query = odbc_exec (odbc_connect("book", "", ""), "
                     SELECT Location_id
                     FROM PITCH
                     WHERE (((PITCH.location_id) NOT IN (SELECT Location_Id FROM BOOKING
                     WHERE StartDate OR EndDate 
                     NOT BETWEEN #$start# -1  AND #$end# +1)) AND ((PITCH.Type_name)='$type'))
        ");
$result = odbc_result_all($query);

echo '<select name="type" id="type">';
While ($row = odbc_fetch_array ($result)) {
   echo "<option> $row </option>";
}
echo '</select>';

您将在$ _GET字段中看到我使用了isset()函数。您应该养成习惯，因为它会检查您提到的字段是否已设置 - 以防止出错。

此外，请在开发计算机上保留错误报告。您可以这样做：

error_reporting(E_ALL);
ini_set('display_errors',1);

Answer 2

<body style="margin: 0px; font-family: Helvetica; font-size: 18px;">
  <header style="background-color: lightsteelblue; padding: 2px;">Hello</header>
  <main style="overflow: auto; background-color: lightgrey; padding: 2px;">
    <article style="height: 400px;">
      Goodbye
    </article>
  </main>
  <footer style="background-color: lightsteelblue; padding: 2px;">I don't know why you say, "Goodbye"; I say, "Hello."</footer>
</body>

来自查询的动态下拉框

2 个答案: