Question

早上好，我有下面的mysql查询显示年份销售情况，直到年度变化，因为它现在显示2012年1月＆amp; 2013年1月合并。

为了尝试解决，我放置了一个下拉表单框（id = YearSelect），其值为2012＆amp; 2013，我可以用选中的值控制这个查询吗？如果最终用户选择2012，那么该值将作为where子句的类型发送到列Year吗？

<form id="yearselect">
<select name="year">
  <option value="">Select year </option>
  <option value="2012">2012</option>
  <option value="2013">2013</option>
</select>
</form>

Select
  *,
  If(q.Adviser Is Null, 1, 0) As remove
From
  (Select
      a.ContactFullName As Adviser,  
      YEAR(b.CaseDate) As Year,
      Sum(If(Month(b.StatusSubmittedDate) = 1, b.CaseCommission, 0)) As Jan,
      Sum(If(Month(b.StatusSubmittedDate) = 2, b.CaseCommission, 0)) As Feb,
      Sum(If(Month(b.StatusSubmittedDate) = 3, b.CaseCommission, 0)) As Mar,
      Sum(If(Month(b.StatusSubmittedDate) = 4, b.CaseCommission, 0)) As Apr,
      Sum(If(Month(b.StatusSubmittedDate) = 5, b.CaseCommission, 0)) As May,
      Sum(If(Month(b.StatusSubmittedDate) = 6, b.CaseCommission, 0)) As Jun,
      Sum(If(Month(b.StatusSubmittedDate) = 7, b.CaseCommission, 0)) As Jul,
      Sum(If(Month(b.StatusSubmittedDate) = 8, b.CaseCommission, 0)) As Aug,
      Sum(If(Month(b.StatusSubmittedDate) = 9, b.CaseCommission, 0)) As Sep,
      Sum(If(Month(b.StatusSubmittedDate) = 10, b.CaseCommission, 0)) As Oct,
      Sum(If(Month(b.StatusSubmittedDate) = 11, b.CaseCommission, 0)) As Nov,
      Sum(If(Month(b.StatusSubmittedDate) = 12, b.CaseCommission, 0)) As Decb,
      Sum(b.CaseCommission) As Total
    From
      tblcontacts a Inner Join
      tblcases b On a.ContactID = b.ContactAssignedTo
    Where
      WHERE Year(b.StatusSubmittedDate) = ".(int)$_POST['year']."
    Group By
      a.ContactFullName WITH ROLLUP
    Having
      Sum(b.CaseCommission) > 0.01) q
Order By
  If(q.Adviser Is Null, 1, 0), q.Total Desc

任何建议表示赞赏。

Answer 1

如何更改此WHERE：

Where
  b.StatusSubmittedDate > '2012 - 01 - 01'

为：

Where
  YEAR(b.StatusSubmittedDate) = ".(int)$YEAR_VALUE_FROM_DROPDOWN."

那应该够了......

Answer 2

考虑到PHP标记，我假设您在PHP基页上显示结果。您可以使用以下代码执行所需操作。

<form id="yearselect" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" >
<select name='selyear' onchange='document.getElementById("yearselect").submit()'>
  <option value=''> - Select year </option>
  <option value='2012'>2012</option>
  <option value='2013'>2013</option>
</select>
</form>

<?
$y = date("Y");
if (isset($_POST['selyear']))
{
  if (checkdate(1, 1, $_POST['selyear']) && $_POST['selyear']>=2012)
    $y = $_POST['selyear'];
}

$query = 'Select
  *,
  If(q.Adviser Is Null, 1, 0) As remove
From
  (Select
      a.ContactFullName As Adviser,  
      YEAR(b.CaseDate) As Year,
      Sum(If(Month(b.StatusSubmittedDate) = 1, b.CaseCommission, 0)) As Jan,
      Sum(If(Month(b.StatusSubmittedDate) = 2, b.CaseCommission, 0)) As Feb,
      Sum(If(Month(b.StatusSubmittedDate) = 3, b.CaseCommission, 0)) As Mar,
      Sum(If(Month(b.StatusSubmittedDate) = 4, b.CaseCommission, 0)) As Apr,
      Sum(If(Month(b.StatusSubmittedDate) = 5, b.CaseCommission, 0)) As May,
      Sum(If(Month(b.StatusSubmittedDate) = 6, b.CaseCommission, 0)) As Jun,
      Sum(If(Month(b.StatusSubmittedDate) = 7, b.CaseCommission, 0)) As Jul,
      Sum(If(Month(b.StatusSubmittedDate) = 8, b.CaseCommission, 0)) As Aug,
      Sum(If(Month(b.StatusSubmittedDate) = 9, b.CaseCommission, 0)) As Sep,
      Sum(If(Month(b.StatusSubmittedDate) = 10, b.CaseCommission, 0)) As Oct,
      Sum(If(Month(b.StatusSubmittedDate) = 11, b.CaseCommission, 0)) As Nov,
      Sum(If(Month(b.StatusSubmittedDate) = 12, b.CaseCommission, 0)) As Decb,
      Sum(b.CaseCommission) As Total
    From
      tblcontacts a Inner Join
      tblcases b On a.ContactID = b.ContactAssignedTo
    Where
      b.StatusSubmittedDate > \''.$y.' - 01 - 01\'
      AND b.StatusSubmittedDate < \''.$y.' - 12 - 31\'
    Group By
      a.ContactFullName WITH ROLLUP
    Having
      Sum(b.CaseCommission) > 0.01) q
Order By
  If(q.Adviser Is Null, 1, 0), q.Total Desc'


  //output results
?>

现在我没有检查你的查询，因为你提到它有效。另外，不是在更改选择列表时发布表单，您也可以将其更改为使用AJAX或其他任何方法来改进它。但我想你明白了。

此外，我现在检查有效年份，而不仅仅是2012年或2013年。这取决于您的需求。

Mysql过滤器查询来自下拉框

2 个答案: