Question

我使用以下语句用ICommandHandlers<>装饰我的所有Decorator1<>：

ObjectFactory.Configure(x =>
{
   x.For(typeof(ICommandHandler<>)).DecorateAllWith(typeof(Decorator1<>));
});

但由于Decorator1<>实现ICommandHandlers<>，Decorator1<>类也会自行修饰。

所以，当我注册所有Decorator1时，问题是ICommandHandler<>无意中注册了。如何过滤DecorateWithAll()来装饰除ICommandHandler<>以外的所有Decorator1<>？

Answer 1

ObjectFactory已过时。

您可以排除Decorator1<>注册为香草ICommandHandler<>，代码如下：

var container = new Container(config =>
{
    config.Scan(scanner =>
    {
        scanner.AssemblyContainingType(typeof(ICommandHandler<>));
        scanner.Exclude(t => t == typeof(Decorator1<>));
        scanner.ConnectImplementationsToTypesClosing(typeof(ICommandHandler<>));
    });
    config.For(typeof(ICommandHandler<>)).DecorateAllWith(typeof(Decorator1<>));
});

<强>更新

对于多个模块，您可以使用The Registry DSL撰写应用程序的一部分

using StructureMap;
using StructureMap.Configuration.DSL;

public class CommandHandlerRegistry : Registry
{
    public CommandHandlerRegistry()
    {
        Scan(scanner =>
        {
            scanner.AssemblyContainingType(typeof(ICommandHandler<>));
            scanner.Exclude(t => t == typeof(Decorator1<>));
            scanner.ConnectImplementationsToTypesClosing(typeof(ICommandHandler<>));
        });
        For(typeof(ICommandHandler<>)).DecorateAllWith(typeof(Decorator1<>));
    }
}

只有组合根需要了解所有Registry实现。

 var container = new Container(config =>
{
    config.AddRegistry<CommandHandlerRegistry>();
});

您甚至可以选择在运行时查找所有Registry实例（您仍需要确保加载所有必需的程序集）

var container = new Container(config =>
{
    var registries = (
        from assembly in AppDomain.CurrentDomain.GetAssemblies()
        from type in assembly.DefinedTypes
        where typeof(Registry).IsAssignableFrom(type)
        where !type.IsAbstract
        where !type.Namespace.StartsWith("StructureMap")
        select Activator.CreateInstance(type))
        .Cast<Registry>();

    foreach (var registry in registries)
    {
        config.AddRegistry(registry);
    }
});

在structure-map 3中为DecorateAllWith（）方法定义过滤器

1 个答案: