Question

我已经设法做了我想要的，但是如果用户与第一个号码不匹配，那么它表示他们没有匹配任何他们可以匹配5等...想想它像一个彩票：）

<?
include "includes/db_connect.php";

$email=$_SESSION["real_name"];
$sql="SELECT * from users WHERE email='$email'";
$result=mysql_query($sql);

while($rows=mysql_fetch_array($result)){ // Start looping table row 

$one2=$rows['1'];
$two2=$rows['2'];
$three2=$rows['3'];
$four2=$rows['4'];
$five2=$rows['5'];
$six2=$rows['6'];
{
        $q = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$one2' OR `2` = '$one2' OR `3` = '$one2' OR `4` = '$one2' OR `5` = '$one2' OR `6` = '$one2' LIMIT 1");
        $get = mysql_num_rows($q);
if($get == 0) {
   echo 'Sorry you didnt match anything';
} else {
    $q1 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$two2' OR `2` = '$two2' OR `3` = '$two2' OR `4` = '$two2' OR `5` = '$two2' OR `6` = '$two2' LIMIT 1");
        $get1 = mysql_num_rows($q1);
if($get1 == 0) {
   echo 'You matched one number';
} else {
    $q2 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$three2' OR `2` = '$three2' OR `3` = '$three2' OR `4` = '$three2' OR `5` = '$three2' OR `6` = '$three2' LIMIT 1");
        $get2 = mysql_num_rows($q2);
if($get2 == 0) {
   echo 'You matched two numbers';
} else {
   $q3 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$four2' OR `2` = '$four2' OR `3` = '$four2' OR `4` = '$four2' OR `5` = '$four2' OR `6` = '$four2' LIMIT 1");
        $get3 = mysql_num_rows($q3);
if($get3 == 0) {
   echo 'You matched three numbers';
} else {
   $q4 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$five2' OR `2` = '$five2' OR `3` = '$five2' OR `4` = '$five2' OR `5` = '$five2' OR `6` = '$five2' LIMIT 1");
        $get4 = mysql_num_rows($q4);
if($get4 == 0) {
   echo 'You matched four numbers';
} else {
    $q5 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$six2' OR `2` = '$six2' OR `3` = '$six2' OR `4` = '$six2' OR `5` = '$six2' OR `6` = '$six2' LIMIT 1");
        $get5 = mysql_num_rows($q5);
if($get5 == 0) {
   echo 'You matched five numbers';
} else {
    echo 'You matched all the numbers';
} 
 ?>


<? }}}}}}} ?>

现在你已经看过代码了，我想我需要解释一下它的更多内容。 one2-six2是用户选择的6个数字。它们需要与“数字”表中的数字相匹配它可以工作，但如果用户不匹配他们的第一个数字（one2）但匹配（two2），那么它表示他们没有匹配任何。

有什么建议吗？

Answer 1

<?
include "includes/db_connect.php";

$email=$_SESSION["real_name"];
$sql="SELECT * from users WHERE email='$email'";
$result=mysql_query($sql);

$number = 0;
$number_wrong = 0;

while($rows=mysql_fetch_array($result)){ // Start looping table row 

$one2=$rows['1'];
$two2=$rows['2'];
$three2=$rows['3'];
$four2=$rows['4'];
$five2=$rows['5'];
$six2=$rows['6'];
{
        $q = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$one2' OR `2` = '$one2' OR `3` = '$one2' OR `4` = '$one2' OR `5` = '$one2' OR `6` = '$one2' LIMIT 1");
        $get = mysql_num_rows($q);
if($get == 0) {
   $number++;
} else {

$number_wrong++;
}
    $q1 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$two2' OR `2` = '$two2' OR `3` = '$two2' OR `4` = '$two2' OR `5` = '$two2' OR `6` = '$two2' LIMIT 1");
        $get1 = mysql_num_rows($q1);
if($get1 == 0) {
   $number++;
} else {

$number_wrong++;
}

    $q2 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$three2' OR `2` = '$three2' OR `3` = '$three2' OR `4` = '$three2' OR `5` = '$three2' OR `6` = '$three2' LIMIT 1");
        $get2 = mysql_num_rows($q2);
if($get2 == 0) {
    $number++;
} else {

$number_wrong++;
}
   $q3 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$four2' OR `2` = '$four2' OR `3` = '$four2' OR `4` = '$four2' OR `5` = '$four2' OR `6` = '$four2' LIMIT 1");
        $get3 = mysql_num_rows($q3);
if($get3 == 0) {
   $number++;
} else {

$number_wrong++;
}
   $q4 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$five2' OR `2` = '$five2' OR `3` = '$five2' OR `4` = '$five2' OR `5` = '$five2' OR `6` = '$five2' LIMIT 1");
        $get4 = mysql_num_rows($q4);
if($get4 == 0) {
$number++;
} else {

$number_wrong++;
}
    $q5 = mysql_query("SELECT * FROM `numbers` WHERE `1` = '$six2' OR `2` = '$six2' OR `3` = '$six2' OR `4` = '$six2' OR `5` = '$six2' OR `6` = '$six2' LIMIT 1");
        $get5 = mysql_num_rows($q5);
if($get5 == 0) {
    $number++;
} else {

$number_wrong++;
}}

Echo 'you got '.$number.' Numbers right and '.$number_wrong.' Numbers wrong.';
 ?>

抱歉在我的手机上这样做了。不是最简单的。请检查语法。

PHP＆amp; Mysql，检查表中的列是否与另一个表中的另一列匹配（复杂）

1 个答案: