Question

好的，我正在尝试更新一个表，具体取决于它是否属于用户，所以在一个表例如我有图片，如下：

+----------------------------------------------------+
| picture_id   |   picture_user   |    picture_title |
+----------------------------------------------------+

在另一张表中我有：

+--------------------------------------------------------------+
| delete_pic_id   |  delete_pic_user  |   delete_pic_status    |
+--------------------------------------------------------------+

现在我只想在delete_pic_user与picture_user匹配时更新delete_pic_status

这就是我的想法，但需要一些帮助：

$manage_application = $database->prepare(
            "UPDATE deleted_pic 
              SET delete_pic_status=1 
             WHERE delete_pic_user(the other table)=the id");

我将如何完成此项

Answer 1

使用Exists

UPDATE deleted_pic
SET    delete_pic_status = 1
WHERE  EXISTS (SELECT 1
               FROM   other_table ot
               WHERE  ot.picture_user = deleted_pic.delete_pic_user)

Answer 2

UPDATE deleted_pic SET delete_pic_status=1 WHERE 
delete_pic_user in (select picture_user from myOthertable)

Answer 3

我假设您正在使用PDO，并且因为您在会话变量中拥有用户的ID，您可以使用像这样的参数化查询

$sth = $database->prepare( "UPDATE deleted_pic 
                              SET delete_pic_status = 1 
                             WHERE delete_pic_user = :id");

$result = $sth->execute(array(':id' => $_SESSION['userId']) );

if ( $result ) {
    // the delete worked
} else {
    // the delete failed
}

Answer 4

以下查询将满足您的需求 -

根据检查另一个表中是否存在来更新所有行

UPDATE deleted_pic dp 
JOIN other_table ot ON ot.picture_user = dp.delete_pic_user
SET delete_pic_status = 1;

在所有行的另一个表中更新一个表的数据 -

UPDATE deleted_pic dp 
JOIN other_table ot ON ot.picture_user = dp.delete_pic_user
SET dp.column1 = ot.column5;

在另一个表中更新特定行的一个表的数据 -

UPDATE deleted_pic dp 
JOIN other_table ot ON ot.picture_user = dp.delete_pic_user
SET dp.column1 = ot.column5
where dp.status=1;

Answer 5

更新deleted_pic SET delete_pic_status = 1 WHERE deleted_pic.delete_pic_user in（SELECT picture_user from tab2）

如果另一个表id匹配，则更新一个表

5 个答案: