我有一个data.frame,我想'清理'列的名称:
>names(Data)
[1] "tBodyAcc.mean...X"
[2] "angle.X.gravityMean."
[3] "fBodyBodyGyroJerkMag.mean.."
[4] "fBodyAccMag.meanFreq.."
.
.
我使用以下代码:
names(Data)<-gsub('[mM]ean',' Mean ',names(Data))
names(Data)<-gsub('[Ff]req',' Frequency ',names(Data))
names(Data)<-gsub('^t','Time ',names(Data))
names(Data)<-gsub('\\.',' ',names(Data))
获取以下内容:
[1] "Time BodyAcc Mean X"
[2] "angle X gravity Mean "
[3] "fBodyBodyGyroJerkMag Mean "
[4] "fBodyAccMag Mean Frequency "
有没有办法在一行或另一行中表达比这一行更优雅的方式?
答案 0 :(得分:1)
由于您需要将每个正则表达式应用于完整向量,因此如果没有某种循环,就无法执行此操作。在下面的示例中,n
是您的names(Data)
向量:
n <- c("tBodyAcc.mean...X", "angle.X.gravityMean.", "fBodyBodyGyroJerkMag.mean..", "fBodyAccMag.meanFreq..")
for(i in seq_along(n)) {
p <- c('[mM]ean', '[Ff]req', '^t', '\\.')
r <- c(' Mean ', ' Frequency ', 'Time ', ' ')
n <- gsub(p[i], r[i], n)
}
结果:
> n
[1] "Time BodyAcc Mean X" "angle X gravity Mean "
[3] "fBodyBodyGyroJerkMag Mean " "fBodyAccMag Mean Frequency "
答案 1 :(得分:1)
您还可以尝试stri_replace_all_regex
包中的stringi
:
library(stringi)
stri_replace_all_regex(names(Data), c("mean", "freq", "^t", "\\."), c(' Mean ', ' Frequency ', 'Time ', ' '), F, list(case_insensitive = TRUE))
# [1] "Time BodyAcc Mean X" "angle X gravity Mean "
# [3] "fBodyBodyGyroJerkMag Mean " "fBodyAccMag Mean Frequency "
答案 2 :(得分:1)
你所拥有的已经相当不错,但前两个正则表达式可以使用ignore.case = TRUE
进行简化。此外,除了最后一个,我们只想更换一次,最好使用sub
代替gsub
:
nms <- c("tBodyAcc.mean...X", "angle.X.gravityMean.",
"fBodyBodyGyroJerkMag.mean..", "fBodyAccMag.meanFreq..")
nms <- sub('mean', ' Mean ', nms, ignore.case = TRUE)
nms <- sub('freq', ' Frequency ', nms, ignore.case = TRUE)
nms <- sub('^t', 'Time ', nms)
nms <- gsub('\\.', ' ', nms)