Question

我有以下示例代码尝试将流传输到gulp.dest（）：

path.js:146
      throw new TypeError('Arguments to path.resolve must be strings');
      ^
TypeError: Arguments to path.resolve must be strings
    at Object.win32.resolve (path.js:146:13)
    at DestroyableTransform.saveFile [as _transform] (C:\paylocity\expense\node_modules\gulp\node_modules\vinyl-fs\lib\dest\index.js:36:26)
    at DestroyableTransform.Transform._read (C:\paylocity\expense\node_modules\gulp\node_modules\vinyl-fs\node_modules\through2\node_modules\readable-stream\lib\_stream_transform.js:184:10)
    at DestroyableTransform.Transform._write (C:\paylocity\expense\node_modules\gulp\node_modules\vinyl-fs\node_modules\through2\node_modules\readable-stream\lib\_stream_transform.js:172:12)
    at doWrite (C:\paylocity\expense\node_modules\gulp\node_modules\vinyl-fs\node_modules\through2\node_modules\readable-stream\lib\_stream_writable.js:237:10)
    at writeOrBuffer (C:\paylocity\expense\node_modules\gulp\node_modules\vinyl-fs\node_modules\through2\node_modules\readable-stream\lib\_stream_writable.js:227:5)
    at DestroyableTransform.Writable.write (C:\paylocity\expense\node_modules\gulp\node_modules\vinyl-fs\node_modules\through2\node_modules\readable-stream\lib\_stream_writable.js:194:11)
    at Readable.ondata (_stream_readable.js:540:20)
    at Readable.emit (events.js:107:17)
    at Readable.read (_stream_readable.js:373:10)

此代码产生以下错误：

var YAML = require('yamljs');

但是，我无法看到代码到底出了什么问题。如果我用process.stdout替换gulp.dest（）然后它工作，gulp.dest（）在其他调用的上下文中工作。这样做的可行方法是什么？

Answer 1

Gulp与乙烯基流合作：

var gulp   = require('gulp'),
    stream = require('stream'),
    source = require('vinyl-source-stream');

var readable = new stream.Readable;
readable.push('Hello, world!');
readable.push(null);

readable
    .pipe(source('test.txt'))
    .pipe(gulp.dest('.'));

Gulp流通常是begins with some file or files as source，因此您需要将该可读流包装到Vinyl stream中，允许Gulp和任何gulp-plugin从文件名中获取信息（显然是假的），避免错误你的。

因此，Gulp流是文件流，只是check the source ...

如何将可读流传输给gulp.dest（）？

1 个答案: