Question

输入：

 bank_details
 payee
 online_system_id
 transaction_id
 pass_num
 prev_tran_approved

 bank_details
 payee
 online_system_id
 transaction_id
 prev_tran_approved

以下代码的实际输出。

  bank_details
 payee
 online_system_id
 transaction_id
 pass_num
 prev_tran_approved
 online_system_id
 proc_online_system_id
 tran_reversed
 prev_tran_approved

 bank_details
 payee
 online_system_id
 transaction_id
 prev_tran_approved
 online_system_id
 proc_online_system_id
 tran_reversed
 prev_tran_approved

预期产出：

 bank_details
 payee
 online_system_id
 transaction_id
 pass_num
 prev_tran_approved
 proc_online_system_id
 tran_reversed

 bank_details
 payee
 online_system_id
 transaction_id
 prev_tran_approved
 proc_online_system_id
 tran_reversed

以下代码仅供参考。即使文件中不存在字符串，我检查文件中现有字符串的if条件总是返回true。请仔细检查代码并建议我进行更改。

好的逻辑是我们必须读取一个包含各行的文件，其中每条记录都以空行分隔。取决于我在if块中提到的条件，即字符串online_system_id是否已经存在于文件中我们不会追加它，如果它不存在，那么我们将在每个记录块的末尾附加它。此检查将针对4个值执行，即online_system_id，proc_online_system_id，tran_reversed，prev_tran_approved

   String line;
    File output = new File(outputDir, "post_tran.tbl");
    PrintStream out = new PrintStream(new FileOutputStream(output));

    BufferedReader br = new BufferedReader(new FileReader(inputFile));
    while((line=br.readLine())!=null){
        if(line.trim().isEmpty()) { 
            if(!(line.contains("online_system_id"))){
                out.println("online_system_id");
            }
            if(!(line.contains("proc_online_system_id"))){
                out.println("proc_online_system_id");
            }    
            if(!(line.contains("tran_reversed"))){
                out.println("tran_reversed");
            }  
            if(!(line.contains("prev_tran_approved"))){
                out.println("prev_tran_approved");
            }  
        }
        out2.println(line);        //always print the current line
      }


      try{
        out2.close(); 
        br.close();
      } catch (Exception ex) {
        System.err.println(ex);
      }

Answer 1

编辑：

在解释了你的逻辑后，看起来你需要跟踪当前记录中出现的4个特殊字符串中的哪一个，并在记录结束时添加其中没有的字符串。你可以使用4个布尔变量来完成它。

boolean osi = false;
boolean posi = false;
boolean tr = false;
boolean pta = false;
while((line=br.readLine())!=null){
    if(line.trim().isEmpty()) { 
        // end of record, print each of the 4 special Strings that didn't appear
        if(!osi){
            out.println("online_system_id");
        }
        if(!posi){
            out.println("proc_online_system_id");
        }    
        if(!tr){
            out.println("tran_reversed");
        }  
        if(!pta){
            out.println("prev_tran_approved");
        }
        osi = false;
        posi = false;
        tr = false;
        pta = false;  
    } else {
        // track appearance of the 4 special Strings
        if(line.contains("online_system_id")){
            osi = true;
        }
        if(line.contains("proc_online_system_id")){
            posi = true;
        }    
        if(line.contains("tran_reversed")){
            tr = true;
        }  
        if(line.contains("prev_tran_approved")){
            pta = true;
        }  
    }
    out.println(line);        //always print the current line
}

Answer 2

变化

if(line.trim().isEmpty())

到

if(!line.trim().isEmpty())

也：

 if((line.contains("online_system_id"))){
                out.println("online_system_id");
            }
            if((line.contains("proc_online_system_id"))){
                out.println("proc_online_system_id");
            }    
            if((line.contains("tran_reversed"))){
                out.println("tran_reversed");
            }  
            if((line.contains("prev_tran_approved"))){
                out.println("prev_tran_approved");
            }

在条件总是失败的情况下附加到文件

2 个答案: