Question

i have a simple json array. in which i have two objects. now i am checking it for some specific values , if found do some thing , if not found do another thing. But i dont know why if condition runs both blocks. true and false both blocks are executed. please help.

$jsonstring = '{"like":[{"username":"abc","password":"abc"},{"username":"def","password":"def"}]}';
$jsonarr = json_decode($jsonstring);
$count = count($jsonarr->like);
for ($r = 0; $r < $count; $r++) 
{
    if ($jsonarr->like[$r]->username == 'abc' && $jsonarr->like[$r]->password == 'abc') 
    { 
         echo 'Match';
    }else
    {
        echo 'No Match';
    }
}

is it not like regular if condition ?

Answer 1

It's showing both blocks because you are looping thru the json array which contains two items. One matching your condition, the other not matching. Here is a simpler version that does not use a loop but just tests your value if in the array. Notice the 'true' flag in the json_decode as well.

<?php

$jsonstring = '{"like":[{"username":"abc","password":"abc"},{"username":"def","password":"def"}]}';
$jsonarr = json_decode($jsonstring, true);

$testArray = $jsonarr['like'];
$loginArray = array('username'=>'abc','password'=>'abc');

if (in_array($loginArray,$testArray)) {
    echo 'match found, do login';
} else {
    echo "no match, do something else";
}
?>

if condition fails while checking json array values

1 个答案: