我想通过收集4个小三角形来制作一个图像背景三角形,就像这个图像
一样
如何制作这个三角形图像背景形状的集合?!
.block {
width: 0;
height: 0;
border: solid 20px;
float: left;
}
.clear {
clear: both;
}
.top {
margin-left: 38px;
}
.top .left {
border-color: transparent green green transparent;
}
.top .right {
border-color: transparent transparent green green;
}
.bottom .left1 {
border-color: transparent red red transparent;
}
.bottom .mid1 {
border-color: blue blue red red;
}
.bottom .mid2 {
border-color: blue purple purple blue;
}
.bottom .right1 {
border-color: transparent transparent purple purple;
}
<div class="top">
<div class="block left"></div>
<div class="block right"></div>
<div class="clear"></div>
</div>
<div class="bottom">
<div class="block left1"></div>
<div class="block mid1"></div>
<div class="block mid2"></div>
<div class="block right1"></div>
</div>
答案 0 :(得分:5)
正如我在评论中提到的,这可能是SVG / canvas是更好的解决方案的情况。我不是他们的专家,但创建一个像你想要的简单模式很简单(I used the background solution from this question):
<svg width="300" height="300">
<defs>
<pattern id="img1" width="100%" height="100%">
<image xlink:href="http://lorempixel.com/200/200/people/" x="0" y="0" width="200" height="200" />
</pattern>
<pattern id="img2" width="100%" height="100%">
<image xlink:href="http://lorempixel.com/200/200/animals/" x="0" y="0" width="200" height="200" />
</pattern>
<pattern id="img3" width="100%" height="100%">
<image xlink:href="http://lorempixel.com/200/200/abstract/" x="0" y="0" width="200" height="200" />
</pattern>
<pattern id="img4" width="100%" height="100%">
<image xlink:href="http://lorempixel.com/200/200/sports/" x="0" y="0" width="200" height="200"/>
</pattern>
</defs>
<path d="M150,0 225,150 75,150" fill="url(#img1)" />
<path d="M0,300 75,150 150,300" fill="url(#img2)" />
<path d="M75,150 225,150 150,300" fill="url(#img3)" />
<path d="M150,300 300,300 225,150" fill="url(#img4)" />
</svg>
编辑:根据以下评论的要求,添加了一些代码来展示如何操作元素(点击两个三角形,它们的图像将交换):
var step = 0;
var $prev;
$("path").on("click", function() {
switch (step) {
// if it's the first step: save the current element for later
case 0:
step = 1;
$prev = $(this);
break;
// if it's the second step: swap images and start again
case 1:
step = 0;
var aux = $prev.attr("fill");
$prev.attr("fill", $(this).attr("fill"));
$(this).attr("fill", aux);
break;
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<svg width="300" height="300">
<defs>
<pattern id="img1" width="100%" height="100%">
<image xlink:href="http://lorempixel.com/200/200/people/" x="0" y="0" width="200" height="200" />
</pattern>
<pattern id="img2" width="100%" height="100%">
<image xlink:href="http://lorempixel.com/200/200/animals/" x="0" y="0" width="200" height="200" />
</pattern>
<pattern id="img3" width="100%" height="100%">
<image xlink:href="http://lorempixel.com/200/200/abstract/" x="0" y="0" width="200" height="200" />
</pattern>
<pattern id="img4" width="100%" height="100%">
<image xlink:href="http://lorempixel.com/200/200/sports/" x="0" y="0" width="200" height="200"/>
</pattern>
</defs>
<path id="path1" stroke="black" d="M150,0 225,150 75,150 150,0" fill="url(#img1)" />
<path id="path2" stroke="black" d="M0,300 75,150 150,300 0,300" fill="url(#img2)" />
<path id="path3" stroke="black" d="M75,150 225,150 150,300 75,150" fill="url(#img3)" />
<path id="path4" stroke="black" d="M150,300 300,300 225,150 150,300" fill="url(#img4)" />
</svg>
你也可以在这个JSFiddle上看到它:http://jsfiddle.net/4x7sh6bj/1/
答案 1 :(得分:3)
使用边框无效......您可以使用剪裁but it isn't well supported。看一下下面的代码:
.imgwrap{
text-align:center;
}
.up{
-webkit-clip-path: polygon(100px 0px, 0px 150px, 200px 150px);
clip-path: polygon(100px 0px, 0px 150px, 200px 150px);
margin:0 -100px;
}
.down{
-webkit-clip-path: polygon(0px 0px, 200px 0px, 100px 150px);
clip-path: polygon(0px 0px, 200px 0px, 100px 150px);
}
<div class="imgwrap">
<img class="down" src="http://www.placehold.it/200x150"/>
<img class="up"src="http://www.placehold.it/200x150"/>
<img class="down"src="http://www.placehold.it/200x150"/>
<br/>
<img class="down"src="http://www.placehold.it/200x150"/>
</div>