我在coredata
中有实体employee_detailname | rate | factor |
_______|______|________|
John | 3.2 | 4 |
Betty | 5.5 | 7 |
Betty | 2.1 | 2 |
Betty | 3.1 | 2 |
Edward | 4.5 | 5 |
John | 2.3 | 4 |
我想要基于属性名称的唯一对象
O / P应该是
name | rate | factor |
_______|______|________|
John | 3.2 | 4 |
Betty | 5.5 | 7 |
Edward | 4.5 | 5 |
答案 0 :(得分:2)
NSFetchRequest *fetchRequest = [NSFetchRequest fetchRequestWithEntityName:@"employee_detail"];
NSEntityDescription *entity = [NSEntityDescription entityForName:@"employee_detail" inManagedObjectContext:self.managedObjectContext];
fetchRequest.resultType = NSDictionaryResultType;
fetchRequest.propertiesToFetch = [NSArray arrayWithObject:[[entity propertiesByName] objectForKey:@"name"]];
fetchRequest.returnsDistinctResults = YES;
NSArray *dictionaries = [self.managedObjectContext executeFetchRequest:fetchRequest error:nil];
NSLog (@"names: %@",dictionaries);