目标:我想从数据库(核心数据)中获取一个属性(来自实体)的值到数组中。
示例
实体名称=员工
Attribute = employeeID
我只想将所有employeeID填充到数组/集中。
问题
鉴于以下是我的实现,我只是觉得它是一种圆形的方式,我想知道是否有更好的方法来做到这一点。
代码
NSFetchRequest *fetchRequest = [NSFetchRequest fetchRequestWithEntityName:@"Employees"];
fetchRequest.resultType = NSDictionaryResultType;
[fetchRequest setPropertiesToFetch:[NSArray arrayWithObjects:@"employeeID", nil]];
NSError *error = nil;
NSArray *results = [self.managedObjectContext executeFetchRequest:fetchRequest
error:&error];
NSMutableArray *employeeIDs = [NSMutableArray array];
for(id currentRecord in results)
{
[employeeIDs addObject:[currentRecord objectForKey:@"employeeID"]];
}
答案 0 :(得分:23)
你可以避免最后一次for循环,
而不是,
NSMutableArray *employeeIDs = [NSMutableArray array];
for(id currentRecord in results)
{
[employeeIDs addObject:[currentRecord objectForKey:@"employeeID"]];
}
试试这个,
NSMutableArray *employeeIDs = [results valueForKey:@"employeeID"];
答案 1 :(得分:17)
这样做的一种方法是 -
NSFetchRequest *fetchRequest = [NSFetchRequest fetchRequestWithEntityName:@"Employees"];
fetchRequest.resultType = NSDictionaryResultType;
NSError *error = nil;
NSArray *results = [self.managedObjectContext executeFetchRequest:fetchRequest
error:&error];
NSMutableArray *employeeIDs = [results valueForKey:@"employeeID"];