Question

这是我的查询

import codecs
f = codecs.open('unicode.rst', encoding='utf-8')
for line in f:
    print repr(line)

我得到select DATEDIFF(minute, '2015-06-10 14:00:00.000', '2015-06-10 16:50:00.000') / 60.0，但我想要2.833333

Answer 1

这可以为您提供所要求的内容，但请注意，通常2.50等于2.5，表示5/2;你正在使用一种非常罕见的符号

DECLARE @f float
DECLARE @t nvarchar(15)

SELECT @f = DATEDIFF(hour, '2015-06-10 14:00:00.000', '2015-06-10 16:50:00.000')
SELECT @t = CONVERT(nvarchar(10), @f) + N'.' + CONVERT(nvarchar(10), (DATEDIFF(minute, '2015-06-10 14:00:00.000', '2015-06-10 16:50:00.000') - @f*60))
SELECT @t

Answer 2

所以你想要显示小时和分钟？你可以用这个：

DECLARE @t1 datetime
SET @t1 = '2015-06-10 14:00:00.000'
DECLARE @t2 datetime
SET  @t2 = '2015-06-10 16:50:00.000'

SELECT HHmm = CONVERT(varchar(3), DATEDIFF(minute, @t1, @t2) / 60) 
             + '.' 
             + RIGHT('0' + CONVERT(varchar(2), DATEDIFF(minute, @t1, @t2) % 60), 2)

Demo

Answer 3

DateDiff函数返回一个整数。将它显示为你需要使用一些数学和铸造的时间：

DECLARE @FromDate datetime = '2015-06-10 14:00:00.000',
        @ToDate datetime = '2015-06-10 16:50:00.000'

select CAST(DATEDIFF(minute, @FromDate, @ToDate) / 60 as varchar) + ':' + 
       CAST(DATEDIFF(minute, @FromDate, @ToDate) % 60 as varchar)

如何从两个日期获得十进制格式的小时和分钟

3 个答案: