Question

我有以下SQL语句：

select top 1 scrr.name, sess.end_time
from tbl_session sess
     inner join tbl_scripts scrr on sess.script_id = scrr.script_id
where end_time >= '5-May-2015 14:58:00'
  and end_time < '06-May-2015 14:58:00'
  and scrr.script_type in (1,3,4)
  and sess.operator_id = 95
UNION
select top 1 scr.name, oh.end_time
from tbl_outbound_history oh
     inner join tbl_outbound o on oh.outbound_id = o.outbound_id
     inner join tbl_session ses on o.session_id = ses.id
     inner join tbl_scripts scr on ses.script_id = scr.script_id
where oh.end_time >= '5-May-2015 14:58:00'
  and oh.end_time < '06-May-2015 14:58:00'
  and oh.start_time <> oh.end_time
  and oh.user_id = 95
order by end_time

数据没有变化，但结果每次都不同。就好像忽略了顺序。

第二个选择在这种情况下不返回任何内容，我尝试简化SQL以最小化问题，但无法重现它。

如果我放弃第二个选择，我每次都得到相同的结果，所以关于联合到零和前1的一些事情或许我可以通过更简单的选择来做到这一点。

之前有人遇到过这样的错误，如果是这样的话，是否有适合它的工作。

任何指向正确方向的人都会受到赞赏。

我正在使用：

Microsoft SQL Server 2012 (SP1) - 11.0.3000.0 (X64) 
    Oct 19 2012 13:38:57 
    Copyright (c) Microsoft Corporation
    Standard Edition (64-bit) on Windows NT 6.1 <X64> (Build 7601: Service Pack 1) (Hypervisor)

Answer 1

您需要订购＆amp;在外部查询中使用top 1

select top 1 from (
select scrr.name, sess.end_time
from tbl_session sess
     inner join tbl_scripts scrr on sess.script_id = scrr.script_id
where end_time >= '5-May-2015 14:58:00'
  and end_time < '06-May-2015 14:58:00'
  and scrr.script_type in (1,3,4)
  and sess.operator_id = 95
UNION
select scr.name, oh.end_time
from tbl_outbound_history oh
     inner join tbl_outbound o on oh.outbound_id = o.outbound_id
     inner join tbl_session ses on o.session_id = ses.id
     inner join tbl_scripts scr on ses.script_id = scr.script_id
where oh.end_time >= '5-May-2015 14:58:00'
  and oh.end_time < '06-May-2015 14:58:00'
  and oh.start_time <> oh.end_time
  and oh.user_id = 95
) a
order by a.end_time

我相信，施放日期时间会很棒

CAST('06-May-2015 14:58:00' as datetime)

SQL Server联合未正确排序

1 个答案: