Question

有人能指出我的sql查询错误的地方，在我获取数据时它没有给出关于SUM的预期结果吗？

我正在尝试计算每个联盟的前5个VAR_MEASURE_1结果，对于第一个联盟我应该得到-7.00但我得到4.00。

编辑 - 这是我使用总和查询之前的数据 -

                VAR_MEASURE_1
16587   SBEN    -14.000 0.000   2014-09-30 00:31:24
16288   SBEN    3.000   0.000   2014-09-30 00:52:46
16288   SBEN    3.000   0.000   2014-09-30 00:53:59
16006   SBEN    5.000   0.000   2014-09-30 01:16:36
15271   SBEN    -4.000  0.000   2014-09-30 01:40:09
15786   SBEN    -6.000  0.000   2014-09-29 00:15:02
16097   SBEN    2.000   0.000   2014-09-29 00:17:34
16097   SBEN    2.000   0.000   2014-09-29 00:19:25
15771   SBEN    -9.000  0.000   2014-09-29 00:38:49
16155   SBEN    7.000   0.000   2014-09-29 01:13:26
15661   SBEN    -9.000  0.000   2014-09-28 17:40:05
14425   SBEN    1.000   0.000   2014-09-28 17:49:09
14425   SBEN    1.000   0.000   2014-09-28 17:50:24
15657   SBEN    -9.000  0.000   2014-09-28 18:02:09
15655   SBEN    -14.000 0.000   2014-09-28 18:24:31

在

之后

                             SUMA
15276   Sample 1    SBEN     4.000  2014-09-30 00:31:24
15855   Sample 2    SBEN    -77.000 2014-09-29 02:40:56
15661   Sample 3    SBEN    -109.000    2014-09-28 17:40:05 







$sql = "(SELECT ID, VARIABLE, VAR_MEASURE_1, doe, CONTRACT_CODE, SUM(VAR_MEASURE_1) AS SUMA  FROM LIVE_VARCOLL WHERE doe between '2014-09-30 00:00:00' AND '2014-09-30 23:59:59' AND CONTRACT_CODE = 'DEC' AND VARIABLE = 'SBEN' LIMIT 5)
    UNION
    (SELECT ID, VARIABLE, VAR_MEASURE_1, doe, CONTRACT_CODE, SUM(VAR_MEASURE_1) AS SUMA FROM LIVE_VARCOLL WHERE doe between '2014-09-29 00:00:01' AND '2014-09-29 23:59:01' AND CONTRACT_CODE = 'DEC' AND VARIABLE = 'SBEN'
    ORDER BY doe LIMIT 5)
    UNION
    (SELECT ID, VARIABLE, VAR_MEASURE_1, doe, CONTRACT_CODE, SUM(VAR_MEASURE_1) AS SUMA FROM LIVE_VARCOLL WHERE doe between '2014-09-28 00:00:01' AND '2014-09-28 23:59:01' AND CONTRACT_CODE = 'DEC' AND VARIABLE = 'SBEN'
    ORDER BY doe LIMIT 5)
    UNION
    (SELECT ID, VARIABLE, VAR_MEASURE_1, doe, CONTRACT_CODE, SUM(VAR_MEASURE_1) AS SUMA FROM LIVE_VARCOLL WHERE doe between '2014-09-27 00:00:01' AND '2014-09-27 23:59:01' AND CONTRACT_CODE = 'DEC' AND VARIABLE = 'SBEN'
    ORDER BY doe LIMIT 5)
    UNION
    (SELECT ID, VARIABLE, VAR_MEASURE_1, doe, CONTRACT_CODE, SUM(VAR_MEASURE_1) AS SUMA FROM LIVE_VARCOLL WHERE doe between '2014-09-26 00:00:01' AND '2014-09-26 23:59:01' AND CONTRACT_CODE = 'DEC' AND VARIABLE = 'SBEN'
    ORDER BY doe LIMIT 5);";

Answer 1

你错误地解释了SUM()的工作方式。

SUM()不限于LIMIT - LIMIT只告诉sql您希望在结果中获得多少行。因此，在您的情况下，每个UNION部分都具有满足要求的所有行的SUM，而不仅仅是前五个。

如果要选择满足特定条件的表的前五行的总和，则应该像下面的示例中那样进行。子查询只检索五行，然后外部查询可以对其进行求和。

要清楚 - 这是用于检索UNIONed查询的第一部分的数据的SQL。您可以尝试构建其他UNION部分：

SELECT tmp.*, SUM(tmp.VAR_MEASURE_1) as SUMA 
   FROM (
      SELECT ID, VARIABLE, VAR_MEASURE_1, doe, CONTRACT_CODE
      FROM LIVE_VARCOLL 
      WHERE doe between '2014-09-30 00:00:00' 
         AND '2014-09-30 23:59:59' 
         AND CONTRACT_CODE = 'DEC' 
         AND VARIABLE = 'SBEN' 
      ORDER BY doe
      LIMIT 5 
   ) tmp

所以你的UNION应该是这样的：

(SELECT tmp.*, SUM(tmp.VAR_MEASURE_1) as SUMA 
    FROM (
       SELECT ID, VARIABLE, VAR_MEASURE_1, doe, CONTRACT_CODE
       FROM LIVE_VARCOLL 
       WHERE doe between '2014-09-30 00:00:00' 
          AND '2014-09-30 23:59:59' 
          AND CONTRACT_CODE = 'DEC' 
          AND VARIABLE = 'SBEN' 
       ORDER BY doe
       LIMIT 5 
    ) tmp)
UNION
(    SELECT tmp.*, SUM(tmp.VAR_MEASURE_1) as SUMA 
    FROM (
       SELECT ID, VARIABLE, VAR_MEASURE_1, doe, CONTRACT_CODE
       FROM LIVE_VARCOLL 
       WHERE doe between '2014-09-29 00:00:00' 
          AND '2014-09-29 23:59:59' 
          AND CONTRACT_CODE = 'DEC' 
          AND VARIABLE = 'SBEN' 
       ORDER BY doe
       LIMIT 5 
    ) tmp)
UNION
( .... more sqls here if needed ... )

但我认为您希望白天获得结果，如果＆＃34; 每天前五行＆＃34;是不重要，您可以选择按天分组的总结果（由DATE(doe)实现）：

 SELECT ID, VARIABLE, VAR_MEASURE_1, doe, DATE(doe) as date_doe, CONTRACT_CODE, SUM(VAR_MEASURE_1) AS SUMA
 FROM LIVE_VARCOLL 
 WHERE CONTRACT_CODE = 'DEC' 
    AND VARIABLE = 'SBEN' 
 GROUP BY DATE(doe)
 ORDER BY DATE(doe)

SUM无法使用UNION - MYSQL正确计算

1 个答案: