Question

使用

创建字符串后

String data = String.valueOf(seekBar1.getProgress()) + ":"
            + String.valueOf(seekBar2.getProgress()) + ":"
            + String.valueOf(seekBar3.getProgress()) + ":"
            + String.valueOf(seekBar4.getProgress()) + ":"
            + String.valueOf(seekBar5.getProgress());

通过蓝牙将此字符串发送到另一台设备，然后使用

byte[] rBuf = (byte[]) msg.obj;
String rMessage = new String(rBuf);
String[] split = rMessage.split(":");
seekBar1.setProgress(Integer.parseInt(split[0]));
seekBar2.setProgress(Integer.parseInt(split[1]));
seekBar3.setProgress(Integer.parseInt(split[2]));
seekBar4.setProgress(Integer.parseInt(split[3]));
seekBar5.setProgress(Integer.parseInt(split[4]));

我得到了

java.lang.NumberFormatException: Invalid int: "0�������������"...

我知道异常是什么，但我不完全确定它被抛出的原因，我已经将收到的数字打印为字符串，据我所知仅整数存在分裂[4] ..

有什么想法在这里发生了什么？可能与InputStream / OutputStream ...

有关

处理蓝牙连接I / O的线程

private class ConnectedThread extends Thread {
        private final BluetoothSocket mmSocket;
        private final InputStream mmInStream;
        private final OutputStream mmOutStream;

        public ConnectedThread(BluetoothSocket socket, String socketType) {
            Log.d(TAG, "create ConnectedThread: " + socketType);
            mmSocket = socket;
            InputStream tmpIn = null;
            OutputStream tmpOut = null;

            // Get the BluetoothSocket input and output streams
            try {
                tmpIn = socket.getInputStream();
                tmpOut = socket.getOutputStream();
            } catch (IOException e) {
                Log.e(TAG, "temp sockets not created", e);
            }

            mmInStream = tmpIn;
            mmOutStream = tmpOut;
        }

        public void run() {
            Log.i(TAG, "BEGIN mConnectedThread");
            byte[] buffer = new byte[1024];
            int bytes;

            // Keep listening to the InputStream while connected
            while (true) {
                try {
                    // Read from the InputStream
                    bytes = mmInStream.read(buffer);

                    // Send the obtained bytes to the UI Activity
                    mHandler.obtainMessage(ControlActivity.MESSAGE_READ, bytes, -1, buffer)
                            .sendToTarget();
                } catch (IOException e) {
                    Log.e(TAG, "disconnected", e);
                    connectionLost();
                    break;
                }
            }
        }

        /**
         * Write to the connected OutStream.
         * @param buffer  The bytes to write
         */
        public void write(byte[] buffer) {
            try {
                mmOutStream.write(buffer);

                // Share the sent message back to the UI Activity
                mHandler.obtainMessage(ControlActivity.MESSAGE_WRITE, -1, -1, buffer)
                        .sendToTarget();
            } catch (IOException e) {
                Log.e(TAG, "Exception during write", e);
            }
        }

        public void cancel() {
            try {
                mmSocket.close();
            } catch (IOException e) {
                Log.e(TAG, "close() of connect socket failed", e);
            }
        }
    }

Answer 1

可能rMessage最后会有一些字符像EOL字符或其他东西。

如果您不想花时间调试you could add a ":" to the end of "data"，

String data = String.valueOf(seekBar1.getProgress()) + ":"
            + String.valueOf(seekBar2.getProgress()) + ":"
            + String.valueOf(seekBar3.getProgress()) + ":"
            + String.valueOf(seekBar4.getProgress()) + ":"
            + String.valueOf(seekBar5.getProgress()) + ":";

这样，您的split[4]仍然合适，只有split[5]无效，无论如何都不会使用。

split（）和parseInt

1 个答案: