我有一个SpatialPolygons(DataFrame)对象,例如SpP
library(sp)
Sr1 = Polygon(cbind(c(2,4,4,1,2),c(2,3,5,4,2)))
Sr2 = Polygon(cbind(c(5,4,2,5),c(2,3,2,2)))
Sr3 = Polygon(cbind(c(4,4,5,10,4),c(5,3,2,5,5)))
Sr4 = Polygon(cbind(c(5,6,6,5,5),c(4,4,3,3,4)), hole = TRUE)
Srs1 = Polygons(list(Sr1), "s1")
Srs2 = Polygons(list(Sr2), "s2")
Srs3 = Polygons(list(Sr3, Sr4), "s3/4")
SpP = SpatialPolygons(list(Srs1,Srs2,Srs3), 1:3)
我想,对于每个多边形,计算其质心(coordinates(SpP)
)与同一多边形内任何其他点之间的最大距离(我假设这个最远的点将位于边缘?)。 / p>
有人可以告诉我该怎么做吗?
答案 0 :(得分:1)
这是我创建的一个简单函数,对于给定的多边形计算质心,使用基本几何体来查找点距离质心最远,返回其坐标:
library(sp)
library(rgeos)
library(ggplot2)
Sr2 = Polygon(cbind(c(5,4,2,5),c(2,3,2,2)))
Srs2=Polygons(list(Sr2), "s2")
spPol=SpatialPolygons(list(Srs2))
find_furthest_point=function(polygon){
coords=fortify(polygon)[,c(1:2)]
center=as.data.frame(gCentroid(polygon))
longs=coords[,1]
lats=coords[,2]
dist_fx=function(long, lat, center=center){
dist=sqrt((long-center[1])^2+(lat-center[2])^2)
return(dist)
}
dists=mapply(dist_fx, longs, lats, MoreArgs=list(center))
furthest_index=as.integer(which(dists==max(dists)))
furthest=coords[furthest_index,]
return(furthest)
}
find_furthest_point(Sr2)