我使用以下代码从我收到的电子邮件文件中测试一些文本检测。
#include <stdio.h>
int main()
{
int max_size = 100;
char email[100] ="aheanstring4strinstringzil.comg";
int pointer = 0;
int i = 1;
int j = 0;
int len = 0;
int chk = 0;
char found1[7] = "string1";
char found2[7] = "string2";
char found3[7] = "string3";
char found4[7] = "string4";
char found5[7] = "string5";
char user1[7] = "string1"; // 23
char user2[7] = "string2";// 19
char user3[7] = "string3"; // 14
char user4[7] = "string4"; // 16
char user5[7] = "string5";; // 15
while (pointer != max_size && chk != 1)
{
for (j = 0;j<7; j++)
{
found1[j] = *(email+pointer+j);
}
if (strcmp(found1, user1) == 0){
printf("Authorized User Found\n");
chk = 1;
continue;
}
for (j = 0;j<7; j++)
{
found2[j] = *(email+pointer+j);
}
if (strcmp(found2, user2) == 0){
printf("Authorized User Found\n");
chk = 1;
continue;
}
for (j = 0;j<7; j++)
{
found3[j] = *(email+pointer+j);
}
if (strcmp(found3, user3) == 0){
printf("Authorized User Found\n");
chk = 1;
continue;
}
for (j = 0;j<7; j++)
{
found4[j] = *(email+pointer+j);
}
if (strcmp(found4, user4) == 0){
printf("Authorized User Found\n");
chk = 1;
continue;
}
for (j = 0;j<7; j++)
{
found5[j] = *(email+pointer+j);
}
if (strcmp(found5, user5) == 0){
printf("Authorized User Found\n");
chk = 1;
continue;
}
pointer++;
}
printf("Check is %d, Pointer is %d\n",chk, pointer);
return 0;
}
我使用上面的代码来查找电子邮件正文中的某些用户。如果找到用户,则while循环中断。当我尝试运行它时,我在上面的变量(电子邮件)中包含了不同的字符串
我尝试在不同的在线C编译器上运行它。所有人都有1,3和5的字符串正常工作。 (被发现)
其中一些人的字符串2工作正常(被检测到)。
然而,他们都分享了从未检测到string2的事实。我不知道为什么。我试着考虑一个原因,但无法弄清楚原因。
我真的很感激一些帮助。
答案 0 :(得分:3)
mfp stop
此处char found1[7] = "string1";
不是C中的有效字符串,因为没有nul终止。你需要
found1
您将char found1[8] = "string1";
传递给found1
,这将导致未定义的行为,因为strcmp()
期望一个空终止的字符串。
或 @Barak Manos 建议你可以选择
strcmp()