所以我正在从JSON文件中读取数据。然后我成功地使用AJAX调用来更新HTML代码中的div。例如:
$( “#carSize”)附加(carInfo [0] .carSize);
div carSize将从JSON文件中获取数据。然而,将有10种不同的汽车具有许多不同的属性,如carSize。由于carInfo数组很大并且具有多个不同的属性,因此有一种方法可以更简单地实现这一点,而无需为每辆汽车的属性创建一个不同的div来附加。
HTML:
<html>
<link href="json.css" rel="stylesheet" type="text/css">
<body>
<div class = "whiteBar">
<div id = "box1">
<div id = "carPrice"></div>
<div id = "carRate"></div>
<a href = "" id = "selBut">SELECT</a>
<div id = "total"></div>
</div>
<div id = "box2">
<div id = "carSize"></div>
</div>
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script src="my_script.js"></script>
</body>
</html>
JS
$(document).ready(function()
{
$.getScript("vehicle_data.json", function()
{
$("#carPrice").append(carInfo[0].carPrice + ".00");
$("#carRate").append(carInfo[0].carRate);
$("#total").append("Total: " + carInfo[0].carPrice * 7 + ".00 USD");
$("#carSize").append(carInfo[0].carSize);
});
});
JSON(样本)
var carInfo = [
{
carId: 1,
carPrice : 35.00,
carRate : 'USD/DAY',
carSize : 'Extra Small Car',
type : 'Economy',
},
{
carId: 2,
carPrice : 37.00,
carRate : 'USD/DAY',
carSize : 'Small Car',
type : 'Compact',
}
];
请注意JS代码仅适用于1辆车,我需要为其他9辆车完成。有什么想法吗?
答案 0 :(得分:1)
创建一个新的div而不是将其附加到现有的html 现在您已将其存储在变量中,您可以附加任何您想要的内容
$.each(carInfo,function(i,car){
//create a new div to store car info
var myNewDiv = $('<div class="car-info"></div>');
// append car properties to the info div
myNewDiv.append(car.carSive);
myNewDiv.append(car.carId); //etc
// append the new div to existing html
$('.whiteBar').append(myNewDiv);
});
答案 1 :(得分:1)
你可以这样做:
$(document).ready(function(){
$.getScript("vehicle_data.json", function() {
for(i=0; i<carInfo.length; i++){
var $carContainer = $('<div class="carContainer-'+i+'"></div>');
$carContainer.append('<div id="carPrice-'+i+'">'+carInfo[i].carPrice + ".00"+'</div>')
.append('<div id="carRate-'+i+'">'+carInfo[i].carRate+'</div>')
.append('<div id="total-'+i+'">'+"Total: " + carInfo[i].carPrice * 7 + ".00 USD"+'</div>')
.append('<div id="carSize-'+i+'">'+carInfo[i].carSize+'</div>');
$('body').append($carContainer);
}
});
});
答案 2 :(得分:0)
如果你一次性购买所有汽车,这是一个通用的解决方案:
var carInfo = [
{
carId: 1,
carPrice : 35.00,
carRate : 'USD/DAY',
carSize : 'Extra Small Car',
type : 'Economy',
},
{
carId: 2,
carPrice : 37.00,
carRate : 'USD/DAY',
carSize : 'Small Car',
type : 'Compact',
}
];
function getCarHTML (car){
var carHtml = '<div class = "box1" class="car-' + car.carId + '" data-id="' + car.carId + '">' +
'<div id = "carPrice">' + car.carPrice + '</div>' +
'<div id = "carRate">' + car.carRate + '</div>' +
'<a href = "" class="select-btn" data-id="' + car.carId + '">SELECT</a>' +
'<div id = "total">' + car.carPrice + '</div>' +
'</div>' +
'<div class = "box2">' +
'<div class = "carSize">' + car.carSize + '</div>' +
'</div>';
return carHtml;
};
//this is your ajax on success function
var showCars = function (cars) {
var $carContainer = $('#car-info-container');
cars.forEach(function(car) {
var carHTML = getCarHTML(car);
var $carIfPreset = $carContainer.find('.car-' + car.carId);
if ($carIfPreset.length) {
$carIfPreset.replaceWith(carHTML);
} else {
$carContainer.append(carHTML);
}
});
};
//calling function here, you should make this call inside your ajax
//Assuming ajax to return an array of cars
showCars(carInfo);
这是一个有效的jsfiddle:https://jsfiddle.net/fjh3mjtm/
预计这里的json是{cars:[{carId:1,carPrice:35.00,...},{carId:2,carPrice:37.00,...},...]}
答案 3 :(得分:0)
我不太确定这是否符合你的需要,但我对jsRender http://www.jsviews.com/有好运,因为这样的情况。