如何使用Android中的JSON从php中的数据库中获取多个数据

Question

它只显示一个值，如ram@gmail.com或ram

JSONObject json = new JSONObject(result);
code = (json.getInt("success"));
if (code ==1) {
    JSONArray user=json.getJSONArray("user");
    JSONObject product = user.getJSONObject(0);

    email1.setText(product.optString("email"));
    name1.setText(product.optString("name"));

    //nid.setText(product.getString("name"));
    Log.v("email",email1.toString());

    Toast.makeText(context,"Data successfully inserted",Toast.LENGTH_SHORT).show();
    Log.i("msg", "Data Successfully Inserted");
    //Data Successfully Inserted
} else {
    Toast.makeText(context,"Data are not successfully inserted",Toast.LENGTH_SHORT).show();
    //Data Not Inserted
}

Answer 1

这是你的意思吗？

 for (int i=0; i < user.length(); i++)
    {
        try {
            JSONObject product = user.getJSONObject(i);
           // product.optString("email")
           // product.optString("name")
        } catch (JSONException e) {

        }
    }