我正在开发一个Android应用程序,我需要在服务器上获取存储在mysql数据库中的数据。从mysql获取数据并显示到android很容易,我没有任何问题。但我不知道如何获取mysql数据,然后将其存储在sqlite数据库中以显示在表视图中。这是我的mysql到android的代码。请帮我如何从mysql中获取数据并存储在sqlite中。
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.view.Menu;
import android.widget.ListView;
import android.widget.SimpleAdapter;
import android.widget.Toast;
public class MainActivity extends Activity
{
private String jsonResult;
private String url = "http://10.0.2.2/database/menu_details.php";
private ListView listView;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
listView = (ListView) findViewById(R.id.listView1);
accessWebService();
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
// Async Task to access the web
private class JsonReadTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(params[0]);
try {
HttpResponse response = httpclient.execute(httppost);
jsonResult = inputStreamToString(
response.getEntity().getContent()).toString();
}
catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
private StringBuilder inputStreamToString(InputStream is) {
String rLine = "";
StringBuilder answer = new StringBuilder();
BufferedReader rd = new BufferedReader(new InputStreamReader(is));
try {
while ((rLine = rd.readLine()) != null) {
answer.append(rLine);
}
}
catch (IOException e) {
// e.printStackTrace();
Toast.makeText(getApplicationContext(),
"Error..." + e.toString(), Toast.LENGTH_LONG).show();
}
return answer;
}
@Override
protected void onPostExecute(String result) {
ListDrwaer();
}
}// end async task
public void accessWebService() {
JsonReadTask task = new JsonReadTask();
// passes values for the urls string array
task.execute(new String[] { url });
}
// build hash set for list view
public void ListDrwaer() {
List<Map<String, String>> menuList = new ArrayList<Map<String, String>>();
try {
JSONObject jsonResponse = new JSONObject(jsonResult);
JSONArray jsonMainNode = jsonResponse.optJSONArray("menu");
for (int i = 0; i < jsonMainNode.length(); i++) {
JSONObject jsonChildNode = jsonMainNode.getJSONObject(i);
String name = jsonChildNode.optString("name");
String id = jsonChildNode.optString("id");
String outPut = name + "-" + id;
menuList.add(createMenu("Menu", outPut));
}
}
catch (JSONException e)
{
Toast.makeText(getApplicationContext(), "Error" + e.toString(),Toast.LENGTH_SHORT).show();
}
SimpleAdapter simpleAdapter = new SimpleAdapter(this, menuList,android.R.layout.simple_list_item_1,
new String[] { "Menu" }, new int[] { android.R.id.text1 });
listView.setAdapter(simpleAdapter);
}
private HashMap<String, String> createMenu(String name, String number) {
HashMap<String, String> menuID = new HashMap<String, String>();
menuID.put(name, number);
return menuID;
}
}
答案 0 :(得分:0)
Follow the steps.
**1. Create table in database handler**
**2. create method in databse handler**
For example:-
` public void addUser(String name, String email,String userage)
{
SQLiteDatabase db = this.getWritableDatabase();
ContentValues values = new ContentValues();
values.put(KEY_NAME, name); // Name
values.put(KEY_EMAIL, email); // Email
}`
**3. you need to create hashmap and other things in database handler**
**4. Userfunction- create same name method in userfunction with params**
then in main activity call the method using json. example
` UserFunctions userFunction = new UserFunctions();
Log.d("Button", "Login");
JSONObject json = userFunction.loginUser(email, password);`
答案 1 :(得分:0)
您应该如何做到这一点:
活动类:
private void registerUser(final String name, final String email, final String password) {
StringRequest strReq = new StringRequest(Request.Method.POST,
AppConfig.URL_INSERT_REGISTER, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.d(TAG, "Register Response: " + response.toString());
hideDialog();
try {
ServiceController iia = new ServiceController(getApplicationContext());
if (iia.isInternetAvailable()) {
JSONObject jObj = new JSONObject(response);
boolean error = jObj.getBoolean("error");
if (!error) {
String uid = jObj.getString("uid");
JSONObject user = jObj.getJSONObject("user");
String name = user.getString("name");
String email = user.getString("email");
//The line below performs the insert to the sqllite database.
db.addUser(name, email, uid);
}
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e(TAG, "Registration Error: " + error.getMessage());
}
}) {
@Override
protected Map<String, String> getParams() {
Map<String, String> params = new HashMap<String, String>();
params.put("name", name);
params.put("email", email);
params.put("password", password);
return params;
}
};
AppController.getInstance().addToRequestQueue(strReq, tag_string_req);
}
在数据库创建类中,您需要添加以下方法:
public void addUser(String name, String email, String uid) {
SQLiteDatabase db = this.getWritableDatabase();
ContentValues params = new ContentValues();
params.put(KEY_NAME, name);
params.put(KEY_EMAIL, email);
params.put(KEY_UID, uid);
long id = db.insert(TABLE_USER, null, params);
db.close();
Log.d(TAG, "New record inserted in table user: " + id);
}
希望这会有所帮助:)