使用getActionCommand的setText问题

时间:2015-05-30 07:22:59

标签: java gettext settext

我是一名初学程序员,试图制作一个简单的计算器。在我的代码结束时,我尝试让文本字段显示用户按下的任何按钮。由于某种原因,text.setText(“7”)不会显示在文本字段中。你能帮帮我吗?

    import javax.swing.*; //imports all that is needed for the code
    import java.awt.*;
    import java.awt.event.*;

    public class Calculator extends JFrame implements ActionListener {

        public JButton button1, button2, button3, button4, button5, button6, button7, button8, button9, button10, button11, button12, button13, button14, button15, button16;
        public JTextArea text;

        public Calculator()
        {
            setSize(350,300); //sets size to 300 by 300 //LOOK UP HOW TO LOCK SIZE
            setResizable(false); //does not let user change the size of the window
            setDefaultCloseOperation(EXIT_ON_CLOSE);//makes app close when I press the x on the top left

            Container contentPane = getContentPane();//gets the contentPane
            contentPane.setBackground(Color.CYAN);//sets background color to white         

            contentPane.setLayout(new FlowLayout());//makes the contentPane read from left to right

            JTextArea text = new JTextArea(1, 25);
            contentPane.add(text);
            text.setEditable(false);

            button1 = new JButton ("7");
            contentPane.add(button1);
            button1.addActionListener(this);

            button2 = new JButton ("8");
            contentPane.add(button2);
            button2.addActionListener(this);

            button3 = new JButton ("9");
            contentPane.add(button3);
            button3.addActionListener(this);

            button4 = new JButton ("÷");
            contentPane.add(button4);
            button4.addActionListener(this);

            button5 = new JButton ("4");
            contentPane.add(button5);
            button5.addActionListener(this);

            button6 = new JButton ("5");
            contentPane.add(button6);
            button6.addActionListener(this);

            button7 = new JButton ("6");
            contentPane.add(button7);
            button7.addActionListener(this);

            button8 = new JButton ("x");
            contentPane.add(button8);
            button8.addActionListener(this);

            button9 = new JButton ("1");
            contentPane.add(button9);
            button9.addActionListener(this);

            button10 = new JButton ("2");
            contentPane.add(button10);
            button10.addActionListener(this);

            button11 = new JButton ("3");
            contentPane.add(button11);
            button11.addActionListener(this);

            button12 = new JButton ("-");
            contentPane.add(button12);
            button12.addActionListener(this);

            button13 = new JButton ("0");
            contentPane.add(button13);
            button13.addActionListener(this);

            button14 = new JButton (".");
            contentPane.add(button14);
            button14.addActionListener(this);

            button15 = new JButton ("=");
            contentPane.add(button15);
            button15.addActionListener(this);

            button16 = new JButton ("+");
            contentPane.add(button16);
            button16.addActionListener(this);



        }

        public static void main(String[] args)
        {
            Calculator guiWindow = new Calculator(); //uses GUI
            guiWindow.setVisible(true); //makes it visible

        }

        public void actionPerformed(ActionEvent e)
        {
            Container contentPane = getContentPane();

            if (e.getActionCommand().equals("7"));
            {
                text.setText("7");
            }






        }

    }

1 个答案:

答案 0 :(得分:2)

看起来你在构造函数中隐藏了你的成员字段JTextArea text。这意味着你没有将JTextArea的实例分配给成员字段,而是分配给构造函数中的局部变量。

使用而不是

JTextArea text = new JTextArea(1, 25);

text = new JTextArea(1, 25);