Question

我正在尝试对图像进行标准化，我应用了公式来执行此操作，但是这样做会遇到一个奇怪的算术运算问题。

这是我的代码：

IM3=imread('mdb022.pgm');
i = IM3(:,:,1);
rtemp = min(i);         % find the min. value of pixels in all the columns (row vector)
rmin=min(rtemp)      % find the min. value of pixel in the image
rtemp = max(i);         % find the max. value of pixels in all the columns (row vector)
rmax=max(rtemp)      % find the max. value of pixel in the image
a=255;
b=rmax-rmin
m=a/b               % find the slope of line joining point (0,255) to (rmin,rmax)
c = 255 - m*rmax;       % find the intercept of the straight line with the axis
i_new = m*i + c;        % transform the image according to new slope

在命令窗口中：

>> contrast_stretching_1

rmin =

    0


rmax =

  221


b =

  221


m =

    1

对于步骤m = a / b，除法应为255除以221，等于1.1538 ......，但为什么matlab显示1？

有人可以告诉我并帮助我解决这个问题吗？

谢谢！

Answer 1

将图像更改为双（或单个）

IM3 = imread('mdb022.pgm');
I   = double(IM3(:,:,1));
rmin = min(I(:));
rmax = max(I(:));
m = 255.0 ./ (rmax - rmin);
I_new = m.*(I - rmax) + 255.0;
% I_new = uint8(I_new); if you want the image as uint8

图像规范化：算术运算问题

1 个答案: