以下是输出示例：
expected output:
cat 100
kite 100
ball 50
我想提取结果，最后一个应该是这样的：
_Ibaseebna1_1 | .7890247 .4173177 -0.45 0.654 .2798256 2.224814
_Ibaseebna1_2 | .8838311 .2739327 -0.40 0.690 .4814483 1.622516
_Ibaseebna1_3 | .7762056 .3459759 -0.57 0.570 .3240211 1.859432
gen | 1.072875 .3515304 0.21 0.830 .5644823 2.039142
iagrv | .9696135 .0108311 -2.76 0.006 .9486157 .991076
_Istudysite_1 | .60195 .1877754 -1.63 0.104 .3266121 1.109401
baseebna1_cat | .9311375 .1199702 -0.55 0.580 .7233404 1.198629
gen | 1.050177 .3304 0.16 0.876 .5668433 1.945638
iagrv | .9701813 .0106488 -2.76 0.006 .949533 .9912787
_Ibaseebna1_1 | 1.852936 1.067927 1.07 0.285 .5987925 5.733826
_Ibaseebna1_2 | 1.894772 1.157542 1.05 0.295 .5721982 6.274333
_Ibaseebna1_3 | 3.209055 1.914574 1.95 0.051 .996636 10.33279
gen | 2.397269 .867482 2.42 0.016 1.179502 4.872308
iagrv | .9593829 .013887 -2.86 0.004 .9325473 .9869908
baseebna1_cat | 1.39457 .1997098 2.32 0.020 1.05328 1.846447
由于我有许多相同模式的变量，所以我使用下面的for循环来尝试提取结果
_Ibaseebna1_1 0.79 0.28 2.22 0.65
_Ibaseebna1_2 0.88 0.48 1.62 0.69
_Ibaseebna1_3 0.78 0.32 1.86 0.57
_baseebna1_cat 0.93 0.72 1.20 0.58
_Ibaseebna1_1 1.85 0.60 5.73 0.29
_Ibaseebna1_2 1.89 0.57 6.27 0.30
_Ibaseebna1_3 3.21 1.00 10.33 0.05
_baseebna1_cat 1.39 1.05 1.85 0.02
但结果不是我所期望的，有人会帮我改进吗？
由于
答案 0 :(得分：1)
$ awk '!/^ /{printf "%-15s %.2f %.2f %.2f %.2f\n",($1~/^_/?"":"_")$1,$3,$7,$8,$6}' file
_Ibaseebna1_1 0.79 0.28 2.22 0.65
_Ibaseebna1_2 0.88 0.48 1.62 0.69
_Ibaseebna1_3 0.78 0.32 1.86 0.57
_Istudysite_1 0.60 0.33 1.11 0.10
_baseebna1_cat 0.93 0.72 1.20 0.58
_Ibaseebna1_1 1.85 0.60 5.73 0.28
_Ibaseebna1_2 1.89 0.57 6.27 0.29
_Ibaseebna1_3 3.21 1.00 10.33 0.05
_baseebna1_cat 1.39 1.05 1.85 0.02