在匹配的样式之前打印行

Question

我需要在匹配的图案之前打印一行。 例子：我有一个这样的文件，

文件为

test file: file1
labalanalma
kaknalknala
user: xyxyxyxyxyxyxyxyyxy
djkdhjkh:whwejewj
jwjkewhjkwe: jkdwhjdweh
etc
etc:etc
Jndwejklhewljk
pattern1: Found
wkjhwekwj
wkjhwekj

我要打印“ pattern1：找到”和“用户：xyxyxyxyxyxyxyxyyxy”（如果首先搜索“ pattern1：找到”，则仅打印从用户开始的行。这是AIX，不是Linux，所以grep -B在这里无法使用。

Answer 1

只需将您的user匹配项放入变量并打印即可：

$ awk '/user:/{u=$0}/pattern/{print $0; print u}' file
pattern1: Found
user: xyxyxyxyxyxyxyxyyxy

Answer 2

此Perl单行代码将起作用。.

$  perl -ne ' $x=$_ if /user:/; print "$_$x" if /pattern1:/ ' match.txt
pattern1: Found
user: xyxyxyxyxyxyxyxyyxy

$