从NSString中的某个字符获取子字符串

Question

如果我最初有一个NSString：

"ABCDE*FGHI"

如何让它变成

"FGHI"

换句话说，从星号开始的所有内容都会保留。

同样，我将如何将其变为：

"ABCDE"

（保留星号的所有内容）

由于

Answer 1

NSString *myString = @"ABCDE*FGHI"; 
NSArray *myArray = [myString componentsSeparatedByString:@"*"];

• myArray的密钥0将包含@“ABCDE”
• 键1将包含@“FGHI”

如果您想要多个字符作为分隔符，
使用componentsSeparatedByCharactersInSet：

NSString *myString = @"ABCDE*FGHI-JKL"; 
NSArray *myArray = [myString componentsSeparatedByCharactersInSet:[NSCharacterSet characterSetWithCharactersInString:@"*-"]];

• myArray的密钥0将包含@“ABCDE”
• 键1将包含@“FGHI”
• 键2将包含@“JKL”

Answer 2

NSString *myString = @"ABCDE*FGHI";
NSString *subString = [myString substringWithRange: NSMakeRange(0, [myString rangeOfString: @"*"].location)];

Answer 3

NSString *myString = @"ABCDE*FGHI";
NSArray *myArray = [myString componentsSeparatedByString:@"*"];

Answer 4

NSString *yourString = @"ABCDE*FGHI";

NSMutableArray * array = [[NSMutableArray alloc] initWithArray:[yourString componentsSeparatedByString:@"*"]];

for(int i =0 ; i < array.count ; i++){
    NSLog(@"- %d : %@ \n",i,[array objectAtIndex:i]);
}